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3 years ago

I need help please :(((( .

Mathematics

1 answer:

exis [7]3 years ago

8 0

Answer:

see explanation

Step-by-step explanation:

If the ratios of the 3 pairs of corresponding sides of the 2 triangles are equal then the triangles are similar

$\frac{15}{5}$ = $\frac{12}{4}$ = $\frac{9}{3}$ = 3

Then the triangles are similar by the SSS postulate

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If 2 angles of 1 triangle are congruent to 2 angles of another triangle then the triangles are similar

∠ A = ∠ p = 27°

∠ B = ∠ Q = 45°

Then Δ ABC and Δ PQR are similar by the AA postulate

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3 years ago

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3 years ago

Does anyone get it please help (math)

Sonja [21]

Answer:

Step-by-step explanation:

In ΔACB and ΔCAD,

AD║BC and AC is a transverse [Given]

∠BCA ≅ ∠DAC [Alternate interior angles]

AC ≅ AC [Reflexive property]

BC ≅ AD [Given]

ΔACB ≅ ΔCAD [By SAS property of congruence]

From the second figure,

In ΔJHG and ΔLKH,

JH ≅ LK [Given]

JG ≅ LH [Given]

GH ≅ HK [Given]

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5 0

3 years ago

Can someone please help I really don’t understand this please explain.

marta [7]

Answer:

The answer is option D.

Step-by-step explanation:

You have to multiply it :

h(x) × g(x) = (h×g)(x)

(h×g)(x) = (x² + 2x)(-3x + 4)

(h×g)(x) = -3x³ + 4x² - 6x² + 8x

(h×g)(x) = -3x³ - 2x² + 8x

4 0

3 years ago

Read 2 more answers

19 POINTS HELP PLEASE! Complete the table and pattern. Determine the common difference. Write the explicit rule.

Sonbull [250]

$a_1=-20,\ a_3=-15\\\\2d=a_3-a_1\to 2d=-15-(-20)\to2d=-15+20\to2d=5\to d=2.5\\\\a_n=a_1+(n-1)d\to a_n=-20+(n-1)(2.5)=-20+2.5n-2.5=2.5n-22.5\\\\a_2=2.5(2)-22.5=5-22.5=-17.5\\\\a_4=2.5(4)-22.5=10-22.5=-12.5\\\\a_6=2.5(6)-22.5=15-22.5=-7.5$

f(n)| -20 | -17.5 | -15 |-12.5| -10 | -7.5 |

First term: -20 Common Difference: 2.5

Explicit Rule: $a_n=2.5n-22.5$ Recursive Rule: $a_1=-20,\ a_n=a_{n-1}+2.5$

$a_1=123,\ a_2=131\\\\d=a_2-a_1\to d=131-123=8\\\\a_n=a_1+(n-1)d\to a_n=123+(n-1)(8)=123+8n-8=8n+115\\\\a_3=8(3)+115=24+115=139\\\\a_5=8(5)+115=40+115=155\\\\a_6=8(6)+115=48+115=163$

f(n)| 123 | 131 | 139 | 147 | 155 | 163 |

First term: 123 Common Difference: 8

Explicit Rule: $a_n=8n+115$ Recursive Rule: $a_1=20,\ a_n=a_{n-1}+8$

3 0

3 years ago