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bija089 [108]
3 years ago
7

The graph of the function is symmetric with respect to the origin.

Mathematics
2 answers:
RSB [31]3 years ago
6 0

Answer:

False

Step-by-step explanation:

If it is symmetric about (0,0) then

f(-x) = -f(x)

That is not true here.

forsale [732]3 years ago
5 0

Answer:

true

Step-by-step explanation:

took the test

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There are n machines in a factory, each of them has defective rate of 0.01. Some maintainers are hired to help machines working.
frosja888 [35]

Answer:

a) 1 - ∑²⁰ˣ_k=0 ((e^-λ) × λ^k) / k!

b) 1 - ∑^(80x/d)_k=0 ((e^-λ) × λ^k) / k!

c) ∑²⁰ˣ_k=0 (3^k)/k! = 0.99e³

Step-by-step explanation:  

Given that;

if n ⇒ ∞

p ⇒ 0

⇒ np = Constant = λ,  we can apply poisson approximation

⇒ Here 'p' is small ( p=0.01)

⇒ if (n=large) we can approximate it as prior distribution

⇒ let the number of defective items be d

so p(d) = ((e^-λ) × λ) / d!

NOW

a)

Let there be x number of repairs, So they will repair 20x machines on time. So if the number of defective machine is greater than 20x they can not repair it on time.

λ[n0.01]

p[ d > 20x ] = 1 - [ d ≤ 20x ]

= 1 - ∑²⁰ˣ_k=0 ((e^-λ) × λ^k) / k!

b)

Similarly in this case if number of machines d > 80x/3;

Then it can not be repaired in time

p[ d > 80x/3 ]

1 - ∑^(80x/d)_k=0 ((e^-λ) × λ^k) / k!

c)

n = 300, lets do it for first case i.e;

p [ d > 20x } ≤ 0.01

1 - ∑²⁰ˣ_k=0 ((e^-λ) × λ^k) / k! = 0.01

⇒ ∑²⁰ˣ_k=0 ((e^-λ) × λ^k) / k! = 0.99

⇒ ∑²⁰ˣ_k=0 (λ^k)/k! = 0.99e^λ

∑²⁰ˣ_k=0 (3^k)/k! = 0.99e³

8 0
2 years ago
Which shows the equation y – x = 3 written in slope-intercept form? Question 1 options: y – x – 3 = 0 y – 2 = x + 3 y = 3x y = x
Kazeer [188]
Y=x+3
you need to add the x to the opposite side to get y by itself
4 0
3 years ago
Could someone help? I got my answer, but I want to check if I’m right.
Taya2010 [7]

Hope it helps you........

3 0
2 years ago
Which equation represents the partial sum of the geometric series?
user100 [1]

Answer:

B

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
The time it takes for an object stopped from a certain speed can be modeled by the equation
yanalaym [24]
Given: 
t = 1/2 √v
v = speed of object meters per second

t = 3 seconds

3 = 1/2 √v
3 * 2 = √v
6 = √v
6² = √v²
36 meters = v

v = 36 meters per second

6 0
3 years ago
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