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Feliz [49]
2 years ago
10

MATH.... TRIANGLE JKL HAS VERTICES...

Mathematics
1 answer:
7nadin3 [17]2 years ago
6 0
<h3>Answer: Choice (d)</h3>

Explanation:

To reflect over the y axis, we apply this rule

(x,y) \to (-x,y)

which says to flip the sign of the x term but keep the y coordinate the same.

So that means something like J(-2,5) becomes J ' (2, 5). The other points are handled in the same fashion and that leads us to choice (d). Points on the y axis will stay where they are.

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Find the product ( x ≠ ? )
dsp73

Answer:

-3

Step-by-step explanation:

if x= -3

the denominator becomes 0 and the fraction becomes undefined.

8 0
3 years ago
PLEASE HELP
ruslelena [56]

Answer:

Rosaria purchased 50 bracelets and 70 necklaces

Step-by-step explanation:

Let the number of bracelets be b and the number of necklaces be n

b + n = 120 •••••(i)

Secondly;

10b + 11n = 1270 ••••(ii)

Total cost of b bracelets at 10 per 1 is 10b

Total cost of n bracelets at 11 per 1 is 11n

Adding both gives 1270

From i, b = 120-n

Substitute this into ii

10(120-n) + 11n = 1270

1200 - 10n + 11n = 1270

n = 1270-1200

n = 70

b = 120-n

b = 120-70

b = 50

4 0
3 years ago
HELP ASAP Use the data below
beks73 [17]

Answer:

Part A:

   -Minimum: 10

   -Q1: 17.5

   -Median: 30

   -Q3: 42.5

   -Maximum: 50

Step-by-step explanation:

Part B: IQR= 25

This shows that the data varies for 25 different numbers. That HALF of the data is between 25 numbers.

Part C: Using a box-and-whisker plot you can interpret the different values. Minimum is the first dot (10), connected to the first line (Q1 which is 17.5), connected by a box to the median (30), connected by a box to the third line (Q3 which is 42.5), connected to the last dot which is the maximum (50). And IQR is Q3-Q1, so 42.5-17.5 which is 25.

8 0
3 years ago
Find the average rate of change of the function over the given intervals. f(x) = 12x3 + 12; [5,7]
AlladinOne [14]
<span>average rate of change = (f(7) - f(5)) / (x7 - x5)
</span>f(7) = <span>12 (7^3) + 12 = 4128
f(5) = </span>12 (5^3) + 12 = 1512

so
average rate of change = (4128 - 1512)/(7-5)
average rate of change = 2616 / 2
average rate of change = 1308

hope it helps
7 0
3 years ago
4
Natali [406]

The ratio of the area of ∆ABC to the area of ∆DEF is; 1:100.

<h3>What is the ratio of the area of ∆ABC to the area of ∆DEF?</h3>

Since, a major criterion for similarity and congruence of triangles is that the ratio of corresponding sides are equal.

On this note, since the task content suggest that the ratio of the perimeters is; 1:10, it follows from conventional mathematics that the ratio of their areas is given as; 1²:10²; 1:100.

Read more on congruent triangles;

brainly.com/question/9217675

#SPJ1

8 0
1 year ago
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