The focus of the parabola -40x = y2 is: (-10, 0) (0, -10) (0, 10) (10, 0)

Mathematics

1 answer:

Luda [366]2 years ago

3 0

Answer:

Option A: (-10,0)

Step-by-step explanation:

The given equation of the parabola is in the form of $y^2=4ax$ where the focus is located at $(a,0)$ . Therefore, the focus of the parabola is $(-10,0)$ .

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Right trapezoid WXYZ is shown. Right trapezoid W X Y Z is shown. Sides X Y and W Z are parallel. Angle W is 73 degrees and angle

Sladkaya [172]

Answer:

∠WXY = 107°

Step-by-step explanation:

In a trapezoid, adjacent angles are supplementary, meaning they add up to 180°. ∠W and ∠WXY are adjacent, so they are supplementary. 180° - 73° = 107°.

Another way to do this is to know that there are 360° in a trapezoid. This is a right trapezoid, so two of the angles are 90°. One angle is 73°. 90° + 90° + 73° = 253°. 360° - 253° = 107°.

I hope this helps :))

3 0

3 years ago

What is the equation, in slope-intercept form, of the line

Sati [7]

Given:

Given that the graph of the equation of the line.

The line that is perpendicular to the given line and passes through the point (2,-1)

We need to determine the equation of the line perpendicular to the given line.

Slope of the given line:

The slope of the given line can be determined by substituting any two coordinates from the line in the slope formula,

$m=\frac{y_2-y_1}{x_2-x_1}$