All categories

2 years ago

The focus of the parabola -40x = y2 is: (-10, 0) (0, -10) (0, 10) (10, 0)

Mathematics

1 answer:

Luda [366]2 years ago

3 0

Answer:

Option A: (-10,0)

Step-by-step explanation:

The given equation of the parabola is in the form of $y^2=4ax$ where the focus is located at $(a,0)$ . Therefore, the focus of the parabola is $(-10,0)$ .

You might be interested in

Add 78, 139, and 14, and then divide by 44.

denpristay [2]

Answer:

5.24, 21/4, or 5 and 1/4

Step-by-step explanation:

78+139+14 = 231

231/44 = 5.25

Or 21/4 (improper fraction)

Or 5 and 1/4 (mixed number)

I'm not exactly sure what you were asking I hope that helps!

8 0

2 years ago

Solve the following questions <br> 1/6x + 2/3=1/4x-1/3

VladimirAG [237]

I hope it helps you ❤️❤️❤️

5 0

3 years ago

Read 2 more answers

-2x + 7 = x-32 i need all the steps

ycow [4]

Answer:

-2x + 7 = x-32

7+32=x+2x

39=3x

x=39/3

x=13

Step-by-step explanation:

5 0

2 years ago

Resistors are labeled 100 Ω. In fact, the actual resistances are uniformly distributed on the interval (95, 103). Find the mean

Zinaida [17]

Answer:

$E[R]$ = 99 Ω

$\sigma_R$ = 2.3094 Ω

P(98<R<102) = 0.5696

Step-by-step explanation:

The mean resistance is the average of edge values of interval.

Hence,

The mean resistance, $E[R] = \frac{a+b}{2} = \frac{95+103}{2} = \frac{198}{2}$ = 99 Ω

To find the standard deviation of resistance, we need to find variance first.

$V(R) = \frac{(b-a)^2}{12} =\frac{(103-95)^2}{12} = 5.333$

Hence,

The standard deviation of resistance, $\sigma_R = \sqrt{V(R)} = \sqrt5.333$ = 2.3094 Ω

To calculate the probability that resistance is between 98 Ω and 102 Ω, we need to find Normal Distributions.

$z_1 = \frac{102-99}{2.3094} = 1.299$

$z_2 = \frac{98-99}{2.3094} = -0.433$

From the Z-table, P(98<R<102) = 0.9032 - 0.3336 = 0.5696

5 0

3 years ago

Wooo i really really loce math

Kruka [31]

Step-by-step explanation:

REALLLYYY???!!!!!!

thx 4 the points..

8 0

2 years ago