45 is 0.9% of what number
2 answers:
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The requested values are found in the attached table
Selected pairs
A(22,160)B(30,172)
find the slope of the line AB
m=(y2-y1)/(x2-x1)=(172-160)/(30-22)=12/8=3/2=1.5m=1.5
one point and slope-------- > A(22.160) m=1.5
y=mx+b
160=1.5(22)+bb=127y=1.5x+127---------- > equation in slope intercept form
<span>If the length of the bone is 12 in------------------ > 12*2.54=30.48 cms
</span>y=1.5x+127- >1.5*30.48+127=172.72 cms
172.72/2.54=68 in
172.72/0.30=575.73 feet
the height estimate of the person before death is 172.72 cms=68 inches=575.73 feet
<span>By the height it could be a man of average height or a tall woman</span>
Selected pairs
A(22,160)B(30,172)
find the slope of the line AB
m=(y2-y1)/(x2-x1)=(172-160)/(30-22)=12/8=3/2=1.5m=1.5
one point and slope-------- > A(22.160) m=1.5
y=mx+b
160=1.5(22)+bb=127y=1.5x+127---------- > equation in slope intercept form
<span>If the length of the bone is 12 in------------------ > 12*2.54=30.48 cms
</span>y=1.5x+127- >1.5*30.48+127=172.72 cms
172.72/2.54=68 in
172.72/0.30=575.73 feet
the height estimate of the person before death is 172.72 cms=68 inches=575.73 feet
<span>By the height it could be a man of average height or a tall woman</span>
Answer:
(4,-22)
Hope this helps!
