Probly the first one it looks right
Since you haven't identified this figure, I'm going to assume that it's a rectangle.
The Perimeter of a rectangle of length L and width W is P = 2L + 2W.
Here you are given the Perimeter and the length, and are to find the width, W.
Solving the above equation for W, we get P - 2L = 2W.
Dividing by 2 (to isolate that W), we get
P
-- - L = W
2
Substitute P= 6 yds and L = 6 feet (or 2 yds), find W (in yards).
Answer:
Step-by-step explanation:
Let
L-----> the length of a rectangle
W---> the width of a rectangle
we know that
-----> equation A
-----> inequality B
The inequality B represent the equation that could be used to find the possible values of the width
The solution for the width of the rectangle is all real numbers greater than 20 units