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2 years ago

You will write a 5-paragraph essay explaining how you would solve the following equation:

Mathematics

1 answer:

sattari [20]2 years ago

3 0

Answer:

$x=0$

Step-by-step explanation:

$\frac{7}{3}(2x+3)+\frac{3}{4}(\frac{x}{5}-\frac{15}{2})=\frac{11}{8}$ <-- Given

$\frac{14}{3}x+7+\frac{3}{20}x-\frac{45}{8}=\frac{11}{8}$ <-- Distributive Property

$\frac{280}{60}x+7+\frac{9}{60}x-\frac{45}{8}=\frac{11}{8}$ <-- Find LCD of x-terms

$\frac{289}{60}x+7-\frac{45}{8}=\frac{11}{8}$ <-- Combine Like Terms

$\frac{289}{60}x+7=\frac{56}{8}$ <-- Add 45/8 to both sides

$\frac{289}{60}x+7}=7$ <-- Simplify Right Side

$\frac{289}{60}x=0$ <-- Subtract 7 on both sides

$x=0$ <-- Divide both sides by 289/60

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A dress needs 3 1/4 yards of fabric to make. If the matching jacket requires 5/6 less yards of fabric. How much fabric is needed

oksian1 [2.3K]

Fabric needs to make a dress = 3 1/4
fabric needs to make jacket= 3 1/4 - 5/6
= 29/12 or 2 5/12
Hence total fabric needed for both pieces is
= 3 1/4 + 2 5/12
= 68/12 or 5 8/12 or 5 2/3 yards

3 0

3 years ago

a bus is leaving the bus station at 5:45 p.m. and it takes 2 days 6 hours 30 minutes to reach a destination if the bus leaves on

Fudgin [204]

Answer:

Monday, at 12:15 AM

Step-by-step explanation:

Do this question in parts. First, add 2 days to Friday to get Sunday at 5:45 PM. Then, add 6 hours to 5:45 to get 11:45 PM. Finally, add 30 minutes to 11:45 PM. That takes you to 12:15, and since you passed midnight, Sunday is now Monday. That means the bus arrives Monday, at 12:15 AM.

8 0

2 years ago

Verify that P = Ce^t /1 + Ce^t is a one-parameter family of solutions to the differential equation dP dt = P(1 − P).

NemiM [27]

Answer:

See verification below

Step-by-step explanation:

We can differentiate P(t) respect to t with usual rules (quotient, exponential, and sum) and rearrange the result. First, note that

$1-P=1-\frac{ce^t}{1+ce^t}=\frac{1+ce^t-ce^t}{1+ce^t}=\frac{1}{1+ce^t}$

Now, differentiate to obtain

$\frac{dP}{dt}=(\frac{ce^t}{1+ce^t})'=\frac{(ce^t)'(1+ce^t)-(ce^t)(1+ce^t)'}{(1+ce^t)^2}$

$=\frac{(ce^t)(1+ce^t)-(ce^t)(ce^t)}{(1+ce^t)^2}=\frac{ce^t+ce^{2t}-ce^{2t}}{(1+ce^t)^2}=\frac{ce^t}{(1+ce^t)^2}$

To obtain the required form, extract a factor in both the numerator and denominator:

$\frac{dP}{dt}=\frac{ce^t}{1+ce^t}\frac{1}{1+ce^t}=P(1-P)$

3 0

3 years ago

Solve for b:<br>10abc - 2d = 3d

gulaghasi [49]

Answer:

b = d/(2ac)

Step-by-step explanation:

10abc - 2d = 3d

Add 2d to each side

10abc - 2d+2d = 3d+2d

10 abc = 5d

Divide each side by 10ac

10 abc/ (10ac) = 5d/10ac

b = d/(2ac)

3 0

3 years ago

"how many different rectangles" can you draw that have a perimeter of 12, 14

amm1812

Perimeter of rectangle = length + length + width + width

To find the combinations, think of two numbers that each multiplied by 2 and added up to give 12 or 14

Rectangle with perimeter 12

Say we take length = 2 and width = 3
Multiply the length by 2 = 2 × 2 = 4
Multiply the width by 3 = 2 × 3 = 6
Then add the answers = 4 + 6 = 10
This doesn't give us perimeter of 12 so we can't have the combination of length = 2 and width = 3

Take length = 4 and width = 2
Perimeter = 4+4+2+2 = 12
This is the first combination we can have

Take length = 5 and width = 1
Perimeter = 5+5+1+1 = 12
This is the second combination we can have

The question doesn't specify whether or not we are limited to use only integers, but if it is, we can only have two combinations of length and width that give perimeter of 12

length = 4 and width = 2
length = 5 and width = 1
--------------------------------------------------------------------------------------------------------------

Rectangle with perimeter of 14

Length = 4 and width = 3
Perimeter = 4+4+3+3 = 14

Length = 5 and width = 2
Perimeter = 5+5+2+2 = 14

Length = 6 and width = 1
Perimeter = 6+6+1+1 = 14

We can have 3 different combinations of length and width

3 0

2 years ago