Answer:
Step-by-step explanation:
u can figure the x and y intercepts by just the equation. U can also figure points by subbing.
example :
6x + 2y = 12......there are 2 ways to find the y intercept....u can either sub in 0 for x and solve for y....or u can put the equation in y = mx + b form where b is ur y int.
y = mx + b form :
6x + 2y = 12
2y = -6x + 12
y = (-6/2)x + 12/2
y = -3x + 6.........so the y int is 6 or (0,6)
or u can sub in 0 for x and solve for y
6x + 2y = 12
6(0) + 2y = 12
2y = 12
y = 12/2
y = 6.........y int is 6....or (0,6)
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to find the x intercept. sub in 0 for y and solve for x
6x + 2y = 12
6x + 2(0) = 12
6x + 0 = 12
6x = 12
x = 12/6
x = 2.....so ur x intercept is 2 or (2,0)
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if u dont have a graph to look at to plot points using the slope, then u can easily sub in any number for x and find y to find points on ur line.
6x + 2y = 12.......pick any number for x...besides 0.....x = 1
6(1) + 2y = 12
6 + 2y = 12
2y = -6 + 12
2y = 6
y = 6/2
y = 3......so one point on this line is : (1,3)
6x + 2y = 12......when x = 2
6(2) + 2y = 12
12 + 2y = 12
2y = 12 - 12
2y = 0
y = 0......and another point is (2,0)
u can keep subbing in any number for x to find y....this will find points on ur line.
