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mash [69]
3 years ago
12

Pls answer will get brainliest!!!

Mathematics
1 answer:
crimeas [40]3 years ago
3 0
By using The half-angle formula

cos X/2 = ±√[(1 + cos X)/ 2]
But we have cos x=2/3
= ±√[(1 + 2/3)/ 2]
= ±√[(5/3 )/ 2]
= ±√[(5/5]
=±√1

Therefore answer is ±1

cos A/2 = ±√[(1 + cos A )/ 2]
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What is the area of this shape?​
s2008m [1.1K]

Answer:

57 sq.cm.

Step-by-step explanation:

7 0
3 years ago
given that 8-sqrt(18) over sqrt(2) = a + b sqrt(2) where a and b are integers find the value of a and b
Novay_Z [31]

Answer:

a = - 3 and b = 4

Step-by-step explanation:

Given

\frac{8-\sqrt{18} }{\sqrt{2} }

Simplify \sqrt{18}

= \sqrt{9(2)} = \sqrt{9} × \sqrt{2} = 3\sqrt{2}

Thus expression can be written as

\frac{8-3\sqrt{2} }{\sqrt{2} }

Multiply numerator/denominator by \sqrt{2}

noting that \sqrt{2} × \sqrt{2} = 2

= \frac{\sqrt{2}(8-3\sqrt{2})  }{\sqrt{2}(\sqrt{2})  }

= \frac{8\sqrt{2}-6 }{2}

Dividing each term on the numerator by 2

= 4\sqrt{2} - 3

= - 3 + 4\sqrt{2}

with a = - 3 and b = 4

6 0
3 years ago
Read 2 more answers
Find the area of the figure
MakcuM [25]

9514 1404 393

Answer:

  24.885 in²

Step-by-step explanation:

Use the formula for the area of a triangle.

  A = 1/2bh . . . . . . . where b is the base length and h is the height perpendicular to the base

  A = 1/2(7.9 in)(6.3 in) = 24.885 in²

_____

<em>Additional comment</em>

The given side lengths cannot form a triangle, as the side shown as 14.7 is too long for the ends of the other segments to connect to. The attachment shows that side should be 11.97 in.

5 0
3 years ago
Given the differential Equation y'+2y=2e^x ;solve this equation using the integration factor; solve for y to get the general sol
SCORPION-xisa [38]

y'+2y=2e^x\Longrightarrow y'=2e^x-2y

If f'(x)=g(x) then y=\int{g(x)dx}

So we extract,

y=\int{2e^x-2x}dx

Which becomes,

y=2e^x-x^2+C

Hope this helps.

r3t40

5 0
3 years ago
Identify the initial amount a and the growth factor b in the exponential function.f(t)=1.4^t
vaieri [72.5K]
Initial amount is when no change has happened or when t=0
that iniital amoun tis 1
the growth factor
welll, it grows by 40% each time of previous times

I would say growth factor of 1.4


f(x)=a(b)^t
f(t)=1(1.4)^t
initial amount is 1
grouth factor is 1.4
6 0
3 years ago
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