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pickupchik [31]
3 years ago
10

If 89 X 25 = 2225 work out 89 x 250?

Mathematics
2 answers:
Andreas93 [3]3 years ago
5 0
89 times 250 is just going to be 22,250. It's just adding one more zero!
joja [24]3 years ago
5 0
So to work this question out
so if 89x25 = 2225 and 89x250= 22250 so basically ur just adding a zero
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Let f(x)=x+1 and g(x)= x^2 – 2. Find f (x)· g(x)
gogolik [260]

9514 1404 393

Answer:

  f(x)·g(x) = x³ +x² -2x -2

Step-by-step explanation:

Substitute the function definitions and simplify.

  f(x)·g(x)

  = (x +1)(x² -2)

  = x(x² -2) +1(x² -2)

  = x³ -2x +x² -2

  f(x)·g(x) = x³ +x² -2x -2

7 0
3 years ago
As part of a new advertising campaign, a beverage company wants to increase the dimensions of their cans by a multiple of 1.12.
olga_2 [115]

Answer:

The new can can hold upto volume of 476.69 cubic centimeters.

Step-by-step explanation:

Diameter of the can = d = 6 cm

Radius of the can = r = 0.5d = 0.5 × 6 cm = 3 cm

Height of the can = h = 12 cm

Company wants to increase the dimensions of their cans by a multiple of 1.12. So, the new dimension will be:

r'= 3 cm × 1.12 = 3.36 cm

h' = 12 cm × 1.12 =13.44 cm

Volume of the = can = V

Volume of a cylinder = \pi r^2h

V=\pi r'^2h'

=3.14\times (3.36 cm)^2\times 13.44 cm=476.6808 cm^3\approx 476.68 cm^3

The new can can hold upto volume of 476.69 cubic centimeters.

3 0
4 years ago
12 men can dig a pond in 8 days. How many men can dig it in 6 days?
nlexa [21]

Answer:

It would be 16 men.

Step-by-step explanation:

Let the number of men dig a pond in 6 day be x. Then,

It is a case of inverse variation.

12 × 8 = 6x

=> 96 = 6x

=> x = 96/6

=> x = 16

Hence, 16 men can dig a pond in 6 days.

5 0
3 years ago
Read 2 more answers
Which of the following represents a number that is a minimum of 2 and a maximum of 5? (x ≤ 2) ∩ (x ≥ 5) (x ≤ 2) (x ≥ 5) (x ≥ 2)
Orlov [11]
The answer will be (x ≥ 2) ∩ (x ≤ 5). Hope it help!
4 0
4 years ago
D = {x|x is a whole number} E = {x|x is a perfect square between 1 and 9} F = {x|x is an even number greater than or equal to 2
Art [367]

First, you have to represent each given set by listing their elements. Observe:


•  D = {x | x is a whole number}

D = <span>ℤ

</span>D = {..., – 3, – 2, – 1, 0, 1, 2, 3, ...}


•  E = {x | x is a perfect square between 1 and 9}

("between" does not include the boundaries)

E = {x | x is a perfect square, 1 < x < 9}

E = {x | x = k²,  k ∈ ℕ  and  1 < x < 9}

E = {2²}

E = {4}


•  F = {x | x is an even number,  2 ≤ x < 9}

F = {2, 4, 6, 8}


So,

D ∩ F

=  {..., – 3, – 2, – 1, 0, 1, 2, 3, ...}   <span>∩   {2, 4, 6, 8}
</span>
=  {2, 4, 6, 8}  ≠  {4, 6}


Therefore, that statement is false.


I hope this helps. =)

8 0
4 years ago
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