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2 years ago

If 32 horses consume 112 kg of grass in a certain period, how much grass will be

Mathematics

1 answer:

Aloiza [94]2 years ago

4 0

Answer:

38.5 kg of grass

Step-by-step explanation:

We can solve this problem by using a proportion. (Kg of grass over horses)

Let x = the amount of grass 11 horses will eat in the same period of time.

112/32 = x/11 Cross multiply

1232 = 32x Divide both sides by 32

x = 38.5

I hope this helped and please mark me as brainliest!

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Find the value of x

dalvyx [7]

Answer:

20..................

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3 years ago

Among all pairs of numbers with a sum 57 find the pair whose product is maximum

GarryVolchara [31]

We know that

comparing the problem with the geometry, the rectangle with the largest area (maximum product of two numbers) is the square.
therefore
The pair of numbers, for 57, is 57/2 or 28.5
so
28.5+28.5----------> 57
28.5*28.5-----------> 812.25

the answer is
the pair is 28.5 and 28.5

3 0

3 years ago

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Licemer1 [7]

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3 years ago

Over the last three evenings, Debra received a total of 110 phone calls at the call center. The second evening, she received 4 t

Elza [17]

Answer:

See below.

Step-by-step explanation:

Total = 110

Let calls on third evening = x

second evening = 4x

first evening = x + 8

=> x + 4x + x + 8 = 110

=> 6x = 102

=> x = 17

First evening = x = 17 calls

Second evening = 4x = 68 calls

Third evening = x + 8 = 25 calls

4 0

2 years ago

Al factorizar el trinomio cuadrado perfecto, obtenemos el siguiente resultado: (que no se como resolver) xd algun pro que sepa r

PolarNik [594]

Answer:

$\displaystyle \frac{100}{81}m^8p^{12}q^{16}z^2-\frac{20}{63}m^5p^7q^8z^5+ \frac{1}{49}m^2p^2z^8=\left(\frac{10}{9}m^4p^{6}q^{8}z-\frac{1}{7}mpz^4\right)^2$

Step-by-step explanation:

Trinomio Cuadrado Perfecto

El producto notable llamado cuadrado de un binomio se expresa como:

$(a-b)^2=a^2-2ab+b^2$

Si se tiene un trinomio, es posible convertirlo en un cuadrado perfecto si cumple con las condiciones impuestas en la fórmula:

* El primer término es un cuadrado perfecto

* El último término es un cuadrado perfecto

* El segundo término es el doble del proudcto de los dos términos del binomio.

Tenemos la expresión:

$\displaystyle \frac{100}{81}m^8p^{12}q^{16}z^2-\frac{20}{63}m^5p^7q^8z^5+ \frac{1}{49}m^2p^2z^8$

Calculamos el valor de a como la raiz cuadrada del primer término del trinomio:

$\displaystyle a=\sqrt{\frac{100}{81}m^8p^{12}q^{16}z^2}$

$\displaystyle a=\frac{10}{9}m^4p^{6}q^{8}z$

Calculamos el valor de a como la raiz cuadrada del primer término del trinomio:

$\displaystyle b=\sqrt{\frac{1}{49}m^2p^2z^8$

$\displaystyle b=\frac{1}{7}mpz^4$

Nos cercioramos de que el término central es 2ab:

$\displaystyle 2ab=2\frac{10}{9}m^4p^{6}q^{8}z\frac{1}{7}mpz^4$

Operando:

$\displaystyle 2ab=\frac{20}{63}m^5p^7q^8z^5$

Una vez verificado, ahora podemos decir que:

$\displaystyle \frac{100}{81}m^8p^{12}q^{16}z^2-\frac{20}{63}m^5p^7q^8z^5+ \frac{1}{49}m^2p^2z^8=\left(\frac{10}{9}m^4p^{6}q^{8}z-\frac{1}{7}mpz^4\right)^2$

5 0

2 years ago