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LekaFEV [45]
2 years ago
7

Which congruence criteria is met in the following scenario? ASA SAS SSS HL AAS

Mathematics
1 answer:
marshall27 [118]2 years ago
6 0
HL, it has those 90° angle signs
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It has 3 factors, 5 x and y
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What is the proability of a blue jay being the next bird papa sees
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Question

each morning papa notes the birds feeding on his birdfeeder. so far this month he has seen 59 blue jays, 68 black crows, 12 red robins and 1 cardinal. What is the probability of a blue jay being the next bird papa sees?

Answer:

Probability is the chance of an event occuring. It is obtained by the formula number of outcomes / total number of possible outcomes. The probability of a blue jay being the next bird papa sees is given by number of blue jays / total number of birds = 59 / (59 +68 + 12 + 1) = 59 / 140 = 0.4214

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3 years ago
8u^8+(-21u^8)<br> Helpppp quick
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\huge\textsf{Hey there!}

\mathsf{8u^8 + (-21u^8)}\\\mathsf{= 8u^2 - 21u^8}\\\large\textsf{COMBINE the LIKE TERMS}\\\mathsf{=(8u^8 - 21u^8)}\\\mathsf{= 8 - 21\rightarrow\boxed{\bf -13}}\\\mathsf{= 8u^2 - 21u^8 \rightarrow \bf -13u^8}\\\\\\\\\boxed{\boxed{\large\textsf{Answer: \bf -13u}\bf ^2}}\huge\checkmark\\\\\\\\\large\textsf{Good luck on your assignment and enjoy your day!}\\\\\\\frak{Amphitrite1040:)}

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3 years ago
(04.02 MC)
diamong [38]

Answer: D, Put it in stocks

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5 0
3 years ago
The weights of cars passing over a bridge has a mean of 3550 lb and a standard deviation of 870 lb. Assume that the weights of t
elena-s [515]

Step-by-step explanation:

Note: Question does not indicate if probability required is for weight to exceed or below 3000 lbs.  So choose appropriate answer accordingly (near the end)

Using the usual notations and formulas,

mean, mu = 3550

standard deviation, sigma = 870

Observed value, X = 3000

We calculate

Z = (X-mu)/sigma = (3000-3550)/870 = -0.6321839

Probability of weight below 3000 lbs

= P(X<3000) = P(z<Z) = P(z<-0.6321839) = 0.2636334

Answer:

Probability that a car randomly selected is less than 3000

= P(X<3000) = 0.2636 (to 4 decimals)

Probability that a car randomly selected is greater than 3000

= 1 - P(X<3000) = 1 - 0.2636 (to 4 decimals) = 0.7364 (to 4 decimals)

5 0
3 years ago
Read 2 more answers
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