Answer:
Step-by-step explanation:
Domain of the function will be,
{x ∈ R | x ≠ -2}
Range of the function is,
{y ∈ R | y ≠ -4}
Intercepts of the function,
Their are no intercepts of the given rational function.
Horizontal asymptotes:
Horizontal line parallel to x-axis representing discontinuity.
y = -4
Vertical asymptotes:
Vertical line parallel to y-axis representing discontinuity.
x = -2
No oblique asymptotes.
Determine whether each equation is a linear equation. ... –2x – 3 = y .... linear. 16. 4y. 2. + 9 = –4. SOLUTION: Since y is squared, the equationcannot be written in standard form.
Answer:
I will answer in a general way because the options are not given.
We know that the area of model A is smaller than the area of model B.
For model A, we have 72 shaded sections, out of 100.
Then the quotient of model A is:
72/100 = 0.72
For model B we have 10 sections, and x shaded ones.
Because model B is greater than model A, we know that:
x/10 should be larger than 72/100
then we have the inequality:
x/10 > 0.72
x > 0.72*10
x > 7.2
And we can not have more than 10 shaded sections (because there is a total of 10 sections) then:
10 ≥ x > 7.2
Then x can be any whole number in that interval.
the possible values of x are:
x = 8
x = 9
x = 10
The answer is 200. 1% is equal to 2, so 100% is equal to 200.
x=-3, y=1
Step-by-step explanation:
Given equations are:
2x-3y=-9 Eqn 1
x+y = - 2 Eqn 2
From eqn 2:
Putting x=-y-2 in eqn 1
Hence,
x=-3, y=1
Keywords: Linear equations, Variables
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