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inysia [295]
3 years ago
11

Chris bought 12.4 gallons of gasoline. There are approximately 3.8 liters in 1 gallon. Which measurement is closetsto the number

of liters of gasoline Chris bought? A 11.44 L B 2.74 L C 47.12 L D 14.20 L2
Mathematics
1 answer:
Damm [24]3 years ago
5 0

Answer:

C 47.12 L

Step-by-step explanation:

1 gallon = 3.8 liters

12.4 gallons = x

Cross Multiply

= 12.4 × 3.8

47.12 liters

Option C is correct

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Put the differential equation 9ty+ety′=yt2+81 into the form y′+p(t)y=g(t) and find p(t) and g(t). p(t)= help (formulas) g(t)= he
alexgriva [62]

Answer:

p(t) = \frac{9t^{3} + 729t  - 1}{e^{t}(t^{2} + 81) }

g(t) = 0

And

The differential equation 9ty + e^{t}y' = \frac{y}{t^{2} + 81 } is  linear and homogeneous

Step-by-step explanation:

Given that,

The differential equation is -

9ty + e^{t}y' = \frac{y}{t^{2} + 81 }

e^{t}y' + (9t - \frac{1}{t^{2} + 81 } )y = 0\\e^{t}y' + (\frac{9t(t^{2} + 81 ) - 1}{t^{2} + 81 } )y = 0\\e^{t}y' + (\frac{9t^{3} + 729t  - 1}{t^{2} + 81 } )y = 0\\y' + [\frac{9t^{3} + 729t  - 1}{e^{t}(t^{2} + 81) } ]y = 0

By comparing with y′+p(t)y=g(t), we get

p(t) = \frac{9t^{3} + 729t  - 1}{e^{t}(t^{2} + 81) }

g(t) = 0

And

The differential equation 9ty + e^{t}y' = \frac{y}{t^{2} + 81 } is  linear and homogeneous.

6 0
3 years ago
3/11 ÷ 3/11<br>and <br>9/10 ÷ 3/5<br><br>PLZ HELP ME<br>​
mafiozo [28]

Answer:

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Step-by-step explanation:

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lozanna [386]

9514 1404 393

Answer:

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Step-by-step explanation:

The x-values are evenly-spaced, so any linear function table will have constant differences between the y-values. Here are the y-differences for the different options:

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3 years ago
Estimate the value of 1573 + 1211<br> - 697.
Mumz [18]

Answer:

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Step-by-step explanation:

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Bingel [31]

Answer:

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