2 years ago

Question 13 HELPPP Thanks

Mathematics

1 answer:

taurus [48]2 years ago

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Your answer is c ur welcome

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V^2+2=8-4v^2 solve the question algebically

iris [78.8K]

Answer:

v = ± sqrt(6/5)

Step-by-step explanation:

v^2+2=8-4v^2

Add 4v^2 to each side

v^2+ 4v^2+2=8-4v^2+ 4v^2

5v^2 +2 = 8

Subtract 2 from each side

5v^2 +2-2 = 8-2

5 v^2 = 6

Divide each side by 5

5v^2 /5 = 6/5

v^2 = 6/5

Take the square root of each side

sqrt(v^2) = ± sqrt(6/5)

v = ± sqrt(6/5)

8 0

3 years ago

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Weights of the vegetables in a field are normally distributed. From a sample Carl Cornfield determines the mean weight of a box

pantera1 [17]

To find the z-score for a weight of 196 oz., use

$z=\frac{x-\mu}{\sigma}=\frac{196-180}{8}=\frac{16}{8}=2$

A table for the cumulative distribution function for the normal distribution (see picture) gives the area 0.9772 BELOW the z-score z = 2. Carl is wondering about the percentage of boxes with weights ABOVE z = 2. The total area under the normal curve is 1, so subtract .9772 from 1.0000.

1.0000 - .9772 = 0.0228, so about 2.3% of the boxes will weigh more than 196 oz.