Work out the area of a parallelogram of base 5m and height 3m
1 answer:
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The domain is about how far left-to-right the graph goes.
In relation to the x-axis, the graph starts at x = –3 (with an open circle at –3) and then continues over to the right forever.
This is the shown in the picture with the red markup.
In interval notation, this is (-3, infinity).
Remember to use that left-to-right orientation for interval notation!
The range is in turn about how low to how high the graph goes.
On the graph, I’d do the same thing I did on the red marked up graph and compare the graph to the y-axis.
The graph starts down at y = –5 (with an open circle at –5) and then continues on up forever.
In interval notation, this is (-5, infinity).
In relation to the x-axis, the graph starts at x = –3 (with an open circle at –3) and then continues over to the right forever.
This is the shown in the picture with the red markup.
In interval notation, this is (-3, infinity).
Remember to use that left-to-right orientation for interval notation!
The range is in turn about how low to how high the graph goes.
On the graph, I’d do the same thing I did on the red marked up graph and compare the graph to the y-axis.
The graph starts down at y = –5 (with an open circle at –5) and then continues on up forever.
In interval notation, this is (-5, infinity).
The two other prime factors are 3 and 11
Answer:
The Proof for
△ABD ≅ △CBD is below
Step-by-step explanation:
Given:
AD = CD .........BD bisect AC
To Prove:
△ABD ≅ △CBD
Proof:
In ΔABD and ΔCBD
BD ≅ BD ....……….{Reflexive Property}
∠ADB ≅ ∠CDB …………..{Measure of each angle is 90°( )}
AD ≅ CD ....……….{ }
ΔABD ≅ ΔCBD .......….{By Side-Angle-Side Congruence test} ...Proved
