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Zinaida [17]
2 years ago
8

If 5/7 of x is 5/21 then what's x?

Mathematics
1 answer:
irinina [24]2 years ago
4 0

\frac{5}{7} \: \:  \:  of \: \:  \:   x =  \frac{5}{21}  \\  =  >  \frac{5x}{7}  =  \frac{5}{21}  \\  =  > 5x =  \frac{5}{21}  \times 7 \\  =  > 5x =  \frac{5}{3}  \\  =  > x =  \frac{5}{3}  \times  \frac{1}{5}  \\  =  > x =  \frac{1}{3}

<u>Answer</u><u>:</u>

<u>x =  \frac{1}{3}</u>

Hope you could get an idea from here.

Doubt clarification - use comment section.

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3 years ago
Write and evaluate the expression. Then, complete the statements. Ten less than the quotient of thirty and a number Evaluate whe
Artyom0805 [142]

Answer:

expression:  (30/t) - 10

evaluation:  30/2 - 10 = 5

Step-by-step explanation:

8 0
3 years ago
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7 0
3 years ago
The path of a projectile launched from a 20-ft-tall tower is modeled by the equation y = -5x2 + 40x + 20. What is the maximum he
Otrada [13]

Answer:

30.49 m

Step-by-step explanation:

To obtain the maximum height, we solve for the value x when dy/dx = 0.

Since, y = -5x² + 40x + 20

dy/dx = d[-5x² + 40x + 20]/dx

dy/dx = -10x + 40

Since dy/dx = 0,

-10x + 40 = 0

-10x = -40

x = -40/-10

x = 4

Substituting x = 4 into the equation for y, we have

y = -5x² + 40x + 20

y = -5(4)² + 40(4) + 20

y = -5(16) + 160 + 20

y = -80 + 160 + 20

y = 80 + 20

y = 100 ft

Since y is in feet, we convert to meters.

Since 1 m = 3.28 ft, 100 ft = 100 ft × 1 m/3.28 ft = 30.49 m

So, the maximum height, in meters  reached by the projectile is 30.49 m

3 0
2 years ago
Help please ASAP quick
IrinaK [193]
Well we know that 18 is 3/5 of 30, so all you have to do is add another zero to your thirty and with doing that you can add a zero to 18. So your final answer is 180!
7 0
3 years ago
Read 2 more answers
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