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Lelu [443]
2 years ago
12

Triangle FGH is similar to JKM.

Mathematics
1 answer:
mario62 [17]2 years ago
8 0

Answer: J = 14.4 cm

Step-by-step explanation:

<em>K is similar to G</em>

So we can find the scale that FHG was dilated by dividing the side length of G by the side length of K

16.56/9.2 = 1.8

So the sides of the triangle KMJ were multiplied by a factor of 1.8

to find m :

25.92/1.8 = 14.4

J = 14.4

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(a) x^2-2x=x \times (x+2) \\\\(b) 6x^2+12x=2\times 3 \times x \times ( x + 2) \\\\(c)  3x^3 - 9x=3\times x \times (x^2 -3) \\\\(d) 4x^2 +28 x^3 = 2 \times 2 \times x \times x \times ( 1+ 7x)

Step-by-step explanation:

To factorize, at first, do factorize all the terms then take the common terms out.

(a) x^2-2x

This can be written as

x^2-2x= x\times x + 2 \times x

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(b) 6x^2+12x

=2\times 3 \times x\times x + 2\times 2 \times 3 \times x

Now, taking 2\times 3\times x common from both the terms, we have

6x^2+12x=2\times 3 \times x \times ( x + 2)

This is the required factorization.

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= 3 \times x \times x \times - 9\times x \\\\ 3x^3 - 9x=3\times x \times (x^2 -3)

This is the required factorization.

(d) 4x^2 +28 x^3

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This is the required factorization.

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3 years ago
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