Draw the structures of two different compounds that have the composition CH3NO2. All three H atoms must remain bonded to the C a
tom and both O atoms must remain bonded to the N atom. Draw the molecules by placing atoms on the grid and connecting them with bonds. Include all hydrogen atoms and nonbonding electrons.
1 answer:
Answer:
The structures are shown below.
Explanation:
Hydrogen has only one electron in the valence shell, carbon has 4, nitrogen has 5 and oxygen has 6. So, to complete the octet (or duet in case of hydrogen) they need, respectively, 1, 4, 3, and 2 electrons.
Thus, each hydrogen will share one electron with carbon, and the last electron of it will be shared with nitrogen, and it will still have 4 electrons to share. It can share 2 electrons with both oxygen, and expand its octet, but it is unstable, thus, it will form a resonance structure (the electrons will be relocated), and charges will be formed. One of the oxygens will share only one electron with nitrogen.
The two structures are shown below.
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Answer:
Check explanation
Explanation:.
NOTE: kindly check for attached file/picture for the graph.
From the graph of absorbance against concentration from the question. We can see that the 0.3 mark absorbance is equivalent to 0.15 M. So, the concentration of CuSO4 is 0.15 M.
The concentration can also be calculated using the Beer-lambert equation for absorbance. The equation is given below;
A= ɛ×C×l --------------------------------------------------------------------------------------(1).
Where A= absorbance, ɛ= molar absorptivity, C= concentration and l= length.
Therefore, the concentration,C will now be; C= A/ ɛ×l. -------------------------------------------------------------------------(2).
Assuming the length,l is 1cm.
Hence, C= 0.300/ ɛ×1.
C= (0.300/ ɛ) M.
