Question

The student dissolves the entire impure sample of in enough distilled water to make of solution. Then the student measures the absorbance of the solution and observes that it is . Determine the concentration of in the solution.

Answer 1

Answer:

Check explanation

Explanation:.

NOTE: kindly check for attached file/picture for the graph.

From the graph of absorbance against concentration from the question. We can see that the 0.3 mark absorbance is equivalent to 0.15 M. So, the concentration of CuSO4 is 0.15 M.

The concentration can also be calculated using the Beer-lambert equation for absorbance. The equation is given below;

A= ɛ×C×l --------------------------------------------------------------------------------------(1).

Where A= absorbance, ɛ= molar absorptivity, C= concentration and l= length.

Therefore, the concentration,C will now be; C= A/ ɛ×l. -------------------------------------------------------------------------(2).

Assuming the length,l is 1cm.

Hence, C= 0.300/ ɛ×1.

C= (0.300/ ɛ) M.