I'll try it.
I just went through this twice on scratch paper. The first time was to
see if I could do it, and the second time was because the first result
I got was ridiculous. But I think I got it.
You said <span><u>3sin²(x) = cos²(x)</u>
Use this trig identity: sin²(x) = 1 - cos²(x)
Plug it into the original equation for (x).
3(1 - cos²(x) ) = cos²(x)
Remove parentheses on the left: 3 - 3cos²(x) = cos²(x)
Add 3cos²(x) to each side: 3 = 4cos²(x)
Divide each side by 4 : 3/4 = cos²(x)
Take the square root of each side: <em>cos(x) = (√3) / 2</em> .
There it is ... the cosine of the unknown angle.
Now you just go look it up in a book with a table cosines,
or else pinch it through your computer or your calculator,
or else just remember that you've learned that
cos( <em><u>30°</u></em> ) = </span><span><span>(√3) / 2 </span>.
</span>
Answer:
Step-by-step explanation:
<h2><u>Lesson : Reducing by factors:</u></h2><h2><u /></h2>
Given :
When you have to reduce a number by a certain factor, you must divide the area with the amount that it is reducing from, therefore,
Answer:
30
Step-by-step explanation:
The midpoint of BC will be a distance from line k that is the average of the distances of B and C: (17+13)/2 = 15. Call that midpoint P. We know distance MP is half of distance MA. This same relationship will hold with respect to the distances from P and A to any line through M. That is, the distance from line k (through M) is twice the distance from P to line k: 30 units.
Answer:
where's the options
Step-by-step explanation:
i think you made a mistake