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alexandr402 [8]
3 years ago
15

Solve the system of equations using substitution: 6x – y = –15 X + 2y = 17

Mathematics
1 answer:
defon3 years ago
3 0

Answer:

x = -1

y = 9

Step-by-step explanation:

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ale4655 [162]

Answer:

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Step-by-step explanation:

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8 0
2 years ago
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2x +1 < 5 what would be the inequality for this ?
Juli2301 [7.4K]

Hey there!


2x + 1 < 5

SUBTRACT 1 to BOTH SIDES

2x + 1 - 1 < 5 - 1

SIMPLIFY IT!
2x < 5 - 1

2x < 4


DIVIDE 2 to BOTH SIDES

2x/2 < 4/2

SIMPLIFY IT!
x < 4/2

x < 2


Therefore, your answer is: x < 2

(The graph is down below)


Good luck on your assignment & enjoy your day!


~Amphitrite1040:)

8 0
2 years ago
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Sulin cuts a ribbon into two pieces in the ratio 5 : 3. The shorter piece is 42 cm long. What is the length of the original ribb
blagie [28]
You divide 42 by 3 then multiply what you get times 5. it should equal 60 cm
8 0
2 years ago
Assume that the radius r of a sphere is expanding at a rate of 40 cm/min. The volume of a sphere is V = 4 3 πr3 and its surface
Scrat [10]

Answer:

The rate of change in surface area when r = 20 cm is 20,106.19 cm²/min.

Step-by-step explanation:

The area of a sphere is given by the following formula:

A = 4\pi r^{2}

In which A is the area, measured in cm², and r is the radius, measured in cm.

Assume that the radius r of a sphere is expanding at a rate of 40 cm/min.

This means that \frac{dr}{dt} = 40

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This is \frac{dA}{dt} when r = 20. So

A = 4\pi r^{2}

Applying implicit differentiation.

We have two variables, A and r, so:

\frac{dA}{dt} = 8r\pi \frac{dr}{dt}

\frac{dA}{dt} = 8*20\pi*40

\frac{dA}{dt} = 20106.19

The rate of change in surface area when r = 20 cm is 20,106.19 cm²/min.

6 0
3 years ago
A coin and a dice are tossed at the same time. ​
Aleksandr-060686 [28]

Answer:

H1, H2, H3, H4, H5, H6, T1, T2, T3, T4, T5, T6

1/12

Step-by-step explanation:

ive done this

4 0
3 years ago
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