Two airplanes leave an airport at the same time and travel in opposite directions. One plane travels 95 km per hour faster than
the other. If the two planes are 3358 kilometers apart 2 after hours, what is the rate of each plane?
1 answer:
Answer:
887 and 792 km per hour
Step-by-step explanation:
Lets call the first plane A and the second B
we know that: a=b+95
We can say that 3358=2b+(2b+190)<=A
When solved, we get 3168=4b
b=792 km per hour.
Go back to step two. A=b+95, so A=792+95=887 km per hour
The two planes rates are 887 km per hour and 792 km per hour.
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