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Sloan [31]
3 years ago
12

Two airplanes leave an airport at the same time and travel in opposite directions. One plane travels 95 km per hour faster than

the other. If the two planes are 3358 kilometers apart 2 after hours, what is the rate of each plane?
Mathematics
1 answer:
andrew-mc [135]3 years ago
8 0

Answer:

887 and 792 km per hour

Step-by-step explanation:

Lets call the first plane A and the second B

we know that: a=b+95

We can say that 3358=2b+(2b+190)<=A

When solved, we get 3168=4b

b=792 km per hour.

Go back to step two. A=b+95, so A=792+95=887 km per hour

The two planes rates are 887 km per hour and 792 km per hour.

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You roll a fair six-sided die twice. Find the probability of rolling a 4 the first time and a number greater than 3 the second t
eimsori [14]

Answer:

1/12

Step-by-step explanation:

P(4 first time and >3 second time)

= (1/6)(3/6)

= 1/12

Hence, Probability is <u>1</u><u>/</u><u>1</u><u>2</u>

6 0
4 years ago
** I need help for this one***
Zepler [3.9K]

Answer:

60

Step-by-step explanation:

the two angles are equal angle x and the one opposite

=180-40

=120 ÷2

=60

8 0
3 years ago
Read 2 more answers
Jacob ran 2/3 of the length of a football field before he was tackled. if the filled is 100 yards long. how far is did Jacob run
alukav5142 [94]


the answer is 66 2/3 of the field


4 0
3 years ago
PLEASE HELP I ONLY NEED THIS TO GET A 100 IN HOMEWORK!!! HELP PLEASE!
DerKrebs [107]

Answer:

12

Step-by-step explanation:

First fraction:

Numerator:

(17/40 + 0.6 - 0.005) = 1.02

1⅕ = 1.2

(1.2 ÷ 1.02)×1.7 = 2

Denominator:

5/6 + 4/3 - 53/30

Lcm: 30

(5×5 + 4×10 - 53)/30

12/30 = 0.4

Fraction value: 2/0.4 = 5

Second fraction:

4.75 + 7.5 = 12.25

33 ÷ 33/7

33 × 7/33 = 7

12.25/7 = 1.75

1.75 ÷ 0.25 = 7

Final answer:

5 + 7 = 12

7 0
3 years ago
The first two terms in an arithmetic progression are -2 and 5. The last term in the progression is the only number in the progre
Rudik [331]

Given:

The first two terms in an arithmetic progression are -2 and 5.

The last term in the progression is the only number in the progression that is greater than 200.

To find:

The sum of all the terms in the progression.

Solution:

We have,

First term : a=-2

Common difference : d = 5 - (-2)

                                      = 5 + 2

                                      = 7

nth term of an A.P. is

a_n=a+(n-1)d

where, a is first term and d is common difference.

a_n=-2+(n-1)(7)

According to the equation, a_n>200.

-2+(n-1)(7)>200

(n-1)(7)>200+2

(n-1)(7)>202

Divide both sides by 7.

(n-1)>28.857

Add 1 on both sides.

n>29.857

So, least possible integer value is 30. It means, A.P. has 30 term.

Sum of n terms of an A.P. is

S_n=\dfrac{n}{2}[2a+(n-1)d]

Substituting n=30, a=-2 and d=7, we get

S_{30}=\dfrac{30}{2}[2(-2)+(30-1)7]

S_{30}=15[-4+(29)7]

S_{30}=15[-4+203]

S_{30}=15(199)

S_{30}=2985

Therefore, the sum of all the terms in the progression is 2985.

6 0
3 years ago
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