A positive real number is added to –2i. Which could be the resulting point?
2 answers:
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The slope of the perpendicular line is the negative reciprocal of that of the given line, so is
-1/(3/5) = -5/3
Then the point-slope equation of the perpendicular line can be written as
y = (-5/3)(x -15) -5
y = (-5/3)x +20
The y-intercept of the perpendicular line is y=20.
-1/(3/5) = -5/3
Then the point-slope equation of the perpendicular line can be written as
y = (-5/3)(x -15) -5
y = (-5/3)x +20
The y-intercept of the perpendicular line is y=20.