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Taya2010 [7]
3 years ago
14

A baby weighed 7.25 lbs at birth At the end of 8 months the baby weighed 2 1/2 times its birth weight how many pounds did the ba

by weigh at the end of 8 months
Mathematics
1 answer:
KengaRu [80]3 years ago
5 0
So 7.25 x 2.5 = 18.125 pounds
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Consider the parabola given by the equation: f(x) = 4x² - 6x - 8 Find the following for this parabola: A) The vertex: Preview B)
jeyben [28]

Answer:

The vertex: (\frac{3}{4},-\frac{41}{4} )

The vertical intercept is: y=-8

The coordinates of the two intercepts of the parabola are (\frac{3+\sqrt{41} }{4} , 0) and (\frac{3-\sqrt{41} }{4} , 0)

Step-by-step explanation:

To find the vertex of the parabola 4x^2-6x-8 you need to:

1. Find the coefficients <em>a</em>, <em>b</em>, and <em>c </em>of the parabola equation

<em>a=4, b=-6, \:and \:c=-8</em>

2. You can apply this formula to find x-coordinate of the vertex

x=-\frac{b}{2a}, so

x=-\frac{-6}{2\cdot 4}\\x=\frac{3}{4}

3. To find the y-coordinate of the vertex you use the parabola equation and x-coordinate of the vertex (f(-\frac{b}{2a})=a(-\frac{b}{2a})^2+b(-\frac{b}{2a})+c)

f(-\frac{b}{2a})=a(-\frac{b}{2a})^2+b(-\frac{b}{2a})+c\\f(\frac{3}{4})=4\cdot (\frac{3}{4})^2-6\cdot (\frac{3}{4})-8\\y=\frac{-41}{4}

To find the vertical intercept you need to evaluate x = 0 into the parabola equation

f(x)=4x^2-6x-8\\f(0)=4(0)^2-6\cdot 0-0\\f(0)=-8

To find the coordinates of the two intercepts of the parabola you need to solve the parabola by completing the square

\mathrm{Add\:}8\mathrm{\:to\:both\:sides}

x^2-6x-8+8=0+8

\mathrm{Simplify}

4x^2-6x=8

\mathrm{Divide\:both\:sides\:by\:}4

\frac{4x^2-6x}{4}=\frac{8}{4}\\x^2-\frac{3x}{2}=2

\mathrm{Write\:equation\:in\:the\:form:\:\:}x^2+2ax+a^2=\left(x+a\right)^2

x^2-\frac{3x}{2}+\left(-\frac{3}{4}\right)^2=2+\left(-\frac{3}{4}\right)^2\\x^2-\frac{3x}{2}+\left(-\frac{3}{4}\right)^2=\frac{41}{16}

\left(x-\frac{3}{4}\right)^2=\frac{41}{16}

\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}

x_1=\frac{\sqrt{41}+3}{4},\:x_2=\frac{-\sqrt{41}+3}{4}

4 0
3 years ago
Alain throws a stone off a bridge into a river below. The stone's height (in meters above the water), xxx seconds after Alain th
Naya [18.7K]
For this case we have the following function:
 h (x) = - 5x ^ 2 + 10x + 15&#10;
 By the time the stone is thrown, x = 0.
 We must evaluate this value of x in the function.
 We have then:
 h (0) = - 5 (0) ^ 2 + 10 (0) +15&#10;&#10;h (0) = 0 + 0 + 15&#10;&#10;h (0) = 15 meters
 Answer:
 The height of the stone at the time is thrown is given by:
 h (0) = 15 meters
4 0
3 years ago
Read 2 more answers
1
kakasveta [241]
1/8 or D, because 1/2 divied by 4 equals 1/8. Hope I helped! I need some help on one question for me.

7 0
3 years ago
Read 2 more answers
Find the slope of the line that passses thruogh 1,5 and 10,9
vichka [17]

Answer:  The slope is 4/9  or -4/-9.

Step-by-step explanation:

(1,5)  

(10,9)   Find the difference in the y values and divide it by the difference in the x values.

5-9= -4

1- 10= -9

-4/-9= 4/9

so the slope is 4/9  

Using the slope we could also find the y-intercept and write the equation.

5=4/9 (1) + b    where b is the y-intercept

  5= 4/9 + b

-4/9   -4/9

b= 41/9  

Now we will have the equation  y= 4/9 + 41/9

4 0
3 years ago
4d^3-10 as <br> verbal expression
Rina8888 [55]
Four times d to the third minus ten
3 0
3 years ago
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