Ask question

Ask question

All categories

3 years ago

14

A baby weighed 7.25 lbs at birth At the end of 8 months the baby weighed 2 1/2 times its birth weight how many pounds did the ba

by weigh at the end of 8 months

1 answer:

KengaRu [80]3 years ago

5 0

So 7.25 x 2.5 = 18.125 pounds

You might be interested in

Consider the parabola given by the equation: f(x) = 4x² - 6x - 8 Find the following for this parabola: A) The vertex: Preview B)

jeyben [28]

Answer:

The vertex: $(\frac{3}{4},-\frac{41}{4} )$

The vertical intercept is: $y=-8$

The coordinates of the two intercepts of the parabola are $(\frac{3+\sqrt{41} }{4} , 0)$ and $(\frac{3-\sqrt{41} }{4} , 0)$

Step-by-step explanation:

To find the vertex of the parabola $4x^2-6x-8$ you need to:

1. Find the coefficients <em>a</em>, <em>b</em>, and <em>c </em>of the parabola equation

<em> $a=4, b=-6, \:and \:c=-8$ </em>

2. You can apply this formula to find x-coordinate of the vertex

$x=-\frac{b}{2a}$ , so

$x=-\frac{-6}{2\cdot 4}\\x=\frac{3}{4}$

3. To find the y-coordinate of the vertex you use the parabola equation and x-coordinate of the vertex ( $f(-\frac{b}{2a})=a(-\frac{b}{2a})^2+b(-\frac{b}{2a})+c$ )

$f(-\frac{b}{2a})=a(-\frac{b}{2a})^2+b(-\frac{b}{2a})+c\\f(\frac{3}{4})=4\cdot (\frac{3}{4})^2-6\cdot (\frac{3}{4})-8\\y=\frac{-41}{4}$

To find the vertical intercept you need to evaluate x = 0 into the parabola equation

$f(x)=4x^2-6x-8\\f(0)=4(0)^2-6\cdot 0-0\\f(0)=-8$

To find the coordinates of the two intercepts of the parabola you need to solve the parabola by completing the square

$\mathrm{Add\:}8\mathrm{\:to\:both\:sides}$

$x^2-6x-8+8=0+8$

$\mathrm{Simplify}$

$4x^2-6x=8$

$\mathrm{Divide\:both\:sides\:by\:}4$

$\frac{4x^2-6x}{4}=\frac{8}{4}\\x^2-\frac{3x}{2}=2$

$\mathrm{Write\:equation\:in\:the\:form:\:\:}x^2+2ax+a^2=\left(x+a\right)^2$

$x^2-\frac{3x}{2}+\left(-\frac{3}{4}\right)^2=2+\left(-\frac{3}{4}\right)^2\\x^2-\frac{3x}{2}+\left(-\frac{3}{4}\right)^2=\frac{41}{16}$

$\left(x-\frac{3}{4}\right)^2=\frac{41}{16}$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

$x_1=\frac{\sqrt{41}+3}{4},\:x_2=\frac{-\sqrt{41}+3}{4}$

4 0

3 years ago

Alain throws a stone off a bridge into a river below. The stone's height (in meters above the water), xxx seconds after Alain th

Naya [18.7K]

For this case we have the following function:
$h (x) = - 5x ^ 2 + 10x + 15
$
By the time the stone is thrown, x = 0.
We must evaluate this value of x in the function.
We have then:
$h (0) = - 5 (0) ^ 2 + 10 (0) +15

h (0) = 0 + 0 + 15

h (0) = 15 meters$
Answer:
The height of the stone at the time is thrown is given by:
h (0) = 15 meters

4 0

3 years ago

Read 2 more answers

kakasveta [241]

1/8 or D, because 1/2 divied by 4 equals 1/8. Hope I helped! I need some help on one question for me.

7 0

3 years ago

Read 2 more answers

Find the slope of the line that passses thruogh 1,5 and 10,9

vichka [17]

Answer: The slope is 4/9 or -4/-9.

Step-by-step explanation:

(1,5)

(10,9) Find the difference in the y values and divide it by the difference in the x values.

5-9= -4

1- 10= -9

-4/-9= 4/9

so the slope is 4/9

Using the slope we could also find the y-intercept and write the equation.

5=4/9 (1) + b where b is the y-intercept

5= 4/9 + b

-4/9 -4/9

b= 41/9

Now we will have the equation y= 4/9 + 41/9

4 0

3 years ago

4d^3-10 as <br> verbal expression

Rina8888 [55]

Four times d to the third minus ten

3 0

3 years ago