Answer:
Step-by-step explanation:
If y = 2x + 1, then dy/dt = 2(dx/dt).
If y = 2x + 1, then y = 2(40) + 1 when 40 is substituted for x. y = 81.
(a) if dx/dt = 3, find dy/dt when x = 4:
Replacing dx/dt with 3 in dy/dt = 2(dx/dt) yields dy/dt = 2(3) = 6.
(b) if dy/dt = 2, find dx/dt when x = 40:
Replacing dy/dt with 2 in dy/dt = 2(dx/dt) results in 2 = 2(dx/dt), so dx/dt must be 1.
Answer:
l think the problem of the is your work is not of the number l got.
x=2
Answer:
Step-by-step explanation:
550 48 6-0 3/16 3/16 800
1000 48 10-10 3/16 3/16 1300
1100 48 11-11 3/16 3/16 1400
1500 48 15-8 3/16 3/16 1650
65 9-0 3/16 3/16 1500
2000 65 11-10 3/16 3/16 2050
2500 65 14-10 3/16 3/16 2275
3000 65 17-8 3/16 3/16 2940
4000 65 23-8 3/16 3/16 3600
5000 72 23-8 1/4 1/4 5800
84 17-8 1/4 1/4 5400
7500 84 26-6 1/4 1/4 7150
96 19-8 1/4 1/4 6400
10000 96 26-6 1/4 5/16 8540
120 17-0 1/4 5/16 8100
12000 96 31-6 1/4 5/16 10500
120 20-8 1/4 5/16 9500
15000 108 31-6 5/16 5/16 13300
120 25-6 5/16 5/16 12150
20000 120 34-6 5/16 5/16 15500
25000 120 42-6 3/8 3/8 22300
30000 120 51-3 3/8 3/8 28000
I uploaded the answer to a file hosting. Here's link:
<h3>
Answer:</h3>
<h3>
Step-by-step explanation:</h3>
If Alex cut his wire 18 times, he ended up with 19 equal pieces. He kept 7, so has 7/19 of his 1/3 of the wire.
Bob cut his wire 20 times, so ended up with 21 pieces, of which he kept 9. So he has 9/21 = 3/7 of his 1/3 of the wire.
Claudia kept 1/13 of her 1/3 of the wire, so has the smallest piece.
Bob kept (3/7)·(1/3)·126 cm = 18 cm.
Alex kept (7/19)·(1/3)·126 cm ≈ 15.47 cm.
Bob kept the longest part of the original wire.
