Question

How many moles of AgNO3 must react to form 0. 854 mol Ag? mol AgNO3.

Answer 1

The moles of silver nitrate required to form 0.854 mol silver ion has been 0.854 mol.

The balanced chemical equation for the dissolution of silver nitrate has been:

$\rm AgNO_3\;\rightarrow\;Ag^+\;+\;NO_3^-$

The aqueous solution of silver nitrate has been dissociated into the constituent silver and nitrate ions.

In a balanced chemical equation, the coefficient has been equivalent to the moles of each reactant forming the moles of product.

From, the balanced equation,

$\rm 1\;mol\;AgNO_3=1\;mol\;Ag$

The given moles of Silver has been 0.854 mol. Thus, the moles of silver nitrate required has been given as:

$\rm 1\;mol\;Ag^+=1\;mol\;AgNO_3\\0.854\;mol\;Ag^+=0.854\;\times\;1\;mol\;AgNO_3\\0.854\;mol\;Ag^+=0.854\;mol\;AgNO_3$

The moles of silver nitrate required to form 0.854 mol silver ion has been 0.854 mol.

For more information about the moles produced, refer to the link:

brainly.com/question/10606802