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Alex777 [14]
3 years ago
8

In which group of the Periodic Table do most of the elements exhibit both positive and negative oxidation states?

Chemistry
1 answer:
Shtirlitz [24]3 years ago
4 0
C i think but you should pick it anyway
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In chemistry, yes...yes it is.
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4 years ago
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A teacher gives a test to two algebra classes. The first class has 18 students, and the second has 24 students. If the average f
Morgarella [4.7K]

Answer:

The <em>C)</em> statement is true.

Explanation:

Let's call <em>x_1</em> the average for the first class and <em>x_2 </em>the average for the second class. The overall average <em>x</em> is then:

x=\frac{x_1*18+x_2*24}{18+24}\\x=\frac{84*18+x_2*24}{42}\\x=\frac{1512+x_2*24}{42}

Since the average is given by <em>Average=\frac{Sum of all values}{Amount of values}</em>. We can now calculate <em>x</em> assuming the maximun and minimun values of <em>x_2</em>, 2400 (which is 100 times 24) and 0 respectivly. That gives:

x=\frac{1512+2400}{42}\\x=93

for it's maximun value and

x=\frac{1512+0}{42}\\x=36

for it's minimun value. So we get that <em>x</em> is between 36% and 93%.

5 0
3 years ago
Given that Kp = 3.5 x 10-4 for the reaction 2 CO(g) &lt;=&gt; C(graphite) + CO2(g), what is the partial pressure of CO2(g) at eq
spin [16.1K]

<u>Answer:</u> The partial pressure of carbon dioxide at equilibrium is 0.0056 atm

<u>Explanation:</u>

The given chemical equation follows:

                     2CO(g)\rightleftharpoons C\text{ (graphite)}+CO_2(g)

<u>Initial:</u>             4.00

<u>At eqllm:</u>       4.00-2x        x                 x

The expression of K_p for above reaction follows:

K_p=\frac{p_{CO_2}}{(p_{CO})^2}

The partial pressure of pure solids and liquids are taken as 1 in the equilibrium constant expression.

We are given:

K_p=3.5\times 10^{-4}

Putting values in above expression, we get:

3.5\times 10^{-4}=\frac{x}{(4-2x)^2}\\\\x=0.0056,718.28

Neglecting the value of x = 718.28 because equilibrium pressure cannot be greater than initial pressure

Partial pressure of CO_2 = 0.0056 atm

Hence, the partial pressure of carbon dioxide at equilibrium is 0.0056 atm

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If a drop of blood is 0.05 mL, how many drops of blood are in a blood collection tube that holds 8 mL ?
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160 drops of blood is needed 
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2.5gm answer ....2/18x22.5
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