Answer:
Increase in the concentration of the reactants (vinegar and baking soda) leads to an increase in the rate of reaction (more volume of CO2 is evolved within a shorter time)
Explanation:
The chemical reaction between baking soda and vinegar in water is shown in the chemical reaction equation below;
NaHCO3(aq) + CH3COOH(aq) ----->CO2(g) + H2O(l) + CH3COONa(aq)
The chemical name of baking soda is sodium bicarbonate (NaHCO3) while vineager is a dilute acetic acid (CH3COOH) solution. This reaction provides a very easy set up in which we can study the effect of concentration on the rate of chemical reaction.
We must have it behind our minds that increase in the concentration of reactant species increases the rate of chemical reaction. Secondly, the rate of the reaction between baking soda and vinegar can be monitored by observing the volume of CO2 evolved and how quickly it evolves from the reaction mixture.
We can now postulate a hypothesis which states that; 'increase in the concentration of the reactants (vinegar and baking soda) leads to an increase in the rate of reaction (more volume of CO2 is evolved within a shorter time).'
If we go ahead to subject this hypothesis to experimental test, it will be confirmed to be true because a greater volume of CO2 will be evolved within a shorter time as the concentration of the reactants increases.
Molecules is the answer i believe
Valence electrons determine its valency ? (The group, as in its oxidation state and stability)
Answer:
[H₃O⁺] = 6.31 x 10⁻³ M.
Explanation:
- To find the hydronium ion concentration [H₃O⁺], we can use the relation:
<em>pH = - log[H₃O⁺].</em>
<em></em>
∴ 2.2 = - log[H₃O⁺].
∴ log[H₃O⁺] = - 2.2
<em>∴ [H₃O⁺] = 6.31 x 10⁻³ M.</em>
Answer:
is usually structurally similar to the substrate.
Explanation:
Competitive inhibitors resemble normal substrate and binds to enzyme at the active site usually and prevents substrate from binding.
Active sites are main location for the substrate-enzyme binding. These sites involve weak as well as reversible bonds between the substrate and the enzyme. These inhibitors bind to the active sites and form weak and reversible bonds. Competitive inhibitors can be dissociated from active site by increasing concentration of the substrates. Substrates has to compete for active site and displace the bound competitive inhibitors.
<u>Hence, correct option is - is usually structurally similar to the substrate.</u>
