What is the correct electron configuration for an element with 5 electrons in
1 answer:
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Answer:
Explanation:
<em>Given:</em>
Mass of ferous (Fe) produced = 750 gram.
<em>To find:</em>
Mass of water produced= ?
<em>Solution:</em>
<em>Molar mass of Fe is 55.84 gram/</em><em>mol</em>
Let's find out the number of moles of ferous produced.
Substituting the given data in above formula.
Now the given reaction is,
- For every 3 mole of production of Fe, 4 mole of waters are produced.
- let for 13.43 moles of Fe x moles of H2O will be produced.
now calculate the number of moles of H2O
mass of one mole of H2O is 18 gram, so we can calculate mass of 17.90 moles.
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Answer:
(a) m = 0.327 m.
(b) m = 4.57 m.
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to solve this problem by firstly considering the fact that the molality is computed by dividing the moles of solute by the kilograms of solvent, in this case water; in such a way, we proceed as follows:
(a) We firstly calculate the moles of 36.2 grams of sucrose as its molar mass is 342.3 g/mol:
Next, the kilograms of water in this case are 0.323 kg so that the molality will be:
(b) In this case, we directly realize that the kilograms of water are now 1.889 kg so that the molality will be:
Clearly, the both of them in molal, m, units.
Regards!