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Vladimir79 [104]
3 years ago
13

What is the slope of the line that passes through points (1/4,3) and (5,8)

Mathematics
1 answer:
Alex73 [517]3 years ago
8 0

Answer:

20/19

Step-by-step explanation:

y2-y1/x2-x1

= 8-3/5-1/4

=20/19

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Solve I2 x- 2I &lt; 8<br>O [xl-3 &lt;x&lt;5)<br>XIX&lt;-3 or x&gt;5)<br>{xl-5 &lt;x&lt;3)​
azamat

Answer: Its b also y u test so ez what grade u in lol?

8 0
3 years ago
You received a $178 per month raise. That was a 5% increase. What was your monthly salary before the increase? Show work please
zzz [600]

Answer: 169.52

Step-by-step explanation

%increase which is 5% =100 x final - initial

                                                   ---------------------

                                                         initial

the initial is $169.52

and the final  $178

3 0
2 years ago
In which set do all of the values make the inequality 2x-1 &lt;10 true?
Andrews [41]
Anything in the negatives like -2*2=-4-1 = -5

Or positive values up to 5

2*5=10-1=9 
4 0
3 years ago
Read 2 more answers
A group of 8 friends (5 girls and 3 boys) plans to watch a movie, but they have only 5 tickets. How many different combinations
blondinia [14]
B is your correct answer
3 0
3 years ago
What are the solutions of the equation 9x4 – 2x2 – 7 = 0? Use u substitution to solve. tions of the equation 9
skelet666 [1.2K]

Answer:

Step-by-step explanation:

Let u^2=x^4\\u = x^2

Subbing in:

9u^2-2u-7=0

a = 9, b = -2, c = -7

The product of a and c is the aboslute value of -63, so a*c = 63.  We need 2 factors of 63 that will add to give us -2.  The factors of 63 are {1, 63}, (3, 21}, {7, 9}.  It looks like the combination of -9 and +7 will work because -9 + 7 = -2.  Plug in accordingly:

9u^2-9u+7u-7=0

Group together in groups of 2:

(9u^2-9u)+(7u-7)=0

Now factor out what's common within each set of parenthesis:

9u(u-1)+7(u-1)=0

We know this combination "works" because the terms inside the parenthesis are identical.  We can now factor those out and what's left goes together in another set of parenthesis:

(u-1)(9u+7)=0

Remember that u=x^2

so we sub back in and continue to factor.  This was originally a fourth degree polynomial; that means we have 4 solutions.

(x^2-1)(9x^2+7)=0

The first two solutions are found withing the first set of parenthesis and the second two are found in other set of parenthesis.  Factoring (x^2-1) gives us that x = 1 and -1.  The other set is a bit more tricky.  If

9x^2+7=0 then

9x^2=-7 and

x^2=-\frac{7}{9}

You cannot take the square root of a negative number without allowing for the imaginary component, i, so we do that:

x=±\sqrt{-\frac{7}{9} }

which will simplify down to

x=±\frac{\sqrt{7} }{3}i

Those are the 4 solutions to the quartic equation.

5 0
4 years ago
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