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alisha [4.7K]
3 years ago
10

Simplify the difference. (6w^2 - 5w - 8) – (7w^2 + 4w - 2)

Mathematics
2 answers:
motikmotik3 years ago
4 0
This was my answer. (6w^2-5w-8)-(7w^2 +4w - 2)=w^2-9w-6
BlackZzzverrR [31]3 years ago
3 0

Answer:

42w^2-20w^2+16

Step-by-step explanation:

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It costs 3 tickets to play a game at the fair. If you spent 21tickets on the game, which equation could you use to solve for the
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➷ The correct option would be D. 3g = 21

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This equation could then be rearranged to find the number of games.

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5 0
3 years ago
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I need some help on this if possible
Sophie [7]

where C is the circumference, d is the diameter and r is the radius.

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If you are given the diameter then use the formula C = πd

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Step-by-step explanation:

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3 years ago
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3 years ago
At her job, Jesse. Earn 9 dollars and 50 cents per hour, she also earns a 60 dollar bonus every month. Jesse needs to earn at le
vichka [17]

Answer:

Jesse needs to work 43 hours in the month to make $400 and $60


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7 0
3 years ago
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In an insect colony there are 270 insects after 9 days. If there were initially 80 insects how long will it take the population
Semenov [28]

Answer:

The time it will take the population to grow to 800 insects is 17 days.

Step-by-step explanation:

The growth function of the insects is exponential.

The exponential growth function is:

y=a(1+r)^{t}

Here,

<em>y</em> = final value

<em>a</em> = initial value

<em>r</em> = growth rate

<em>t</em> = time taken

It is provided that there were 270 insects after 9 days and initially there were 80 insects.

Compute the value of <em>r</em> as follows:

y=a(1+r)^{t}\\\\270=80(1+r)^{9}\\\\3.375=(1+r)^{9}\\\\\ln(3.375)=9\cdot \ln(1+r)\\\\0.135155=\ln(1+r)\\\\1+r=1.14471\\\\r=0.145

Now, compute the time it will take the population to grow to 800 insects as follows:

800=80(1+0.145)^{t}\\\\10=(1.145)^{t}\\\\\ln(10)=t\cdot \ln(1.145)\\\\t=17.00522\\\\t\approx 17

Thus, the time it will take the population to grow to 800 insects is 17 days.

7 0
3 years ago
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