NEED ASAP

Mathematics

1 answer:

Nastasia [14]3 years ago

4 0

Answer:

5700

Step-by-step explanation:

Assume that the total number of people working for the company is x. Since 65% of workers are men and 1,995 people working for the working are not men, then that means that 35% of the total number of people working for the company is equal 1,995.

Set up an equation: 0.35x = 1,995 and find x.

x = 5700

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What is the answer to this question

stich3 [128]

Answer:

Step-by-step explanation:

Given the exponential function

f(t) = 228 $(0.975)^{t}$ ← where t is time in years

Substitute t = 20 into f(t), that is

f(20) = 228 × $(0.975)^{20}$ = 228 × 0.60268.... ≈ 137 → A

4 0

3 years ago

Evaluate the line integral, where c is the given curve. (x + 9y) dx + x2 dy, c c consists of line segments from (0, 0) to (9, 1)

viktelen [127]

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=\int_C\langle x+9y,x^2\rangle\cdot\underbrace{\langle\mathrm dx,\mathrm dy\rangle}_{\mathrm d\mathbf r}$

The first line segment can be parameterized by $\mathbf r_1(t)=\langle0,0\rangle(1-t)+\langle9,1\rangle t=\langle9t,t\rangle$ with $0\le t\le1$ . Denote this first segment by $C_1$ . Then

$\displaystyle\int_{C_1}\langle x+9y,x^2\rangle\cdot\mathbf dr_1=\int_{t=0}^{t=1}\langle9t+9t,81t^2\rangle\cdot\langle9,1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(162t+81t^2)\,\mathrm dt$
$=108$

The second line segment ( $C_2$ ) can be described by $\mathbf r_2(t)=\langle9,1\rangle(1-t)+\langle10,0\rangle t=\langle9+t,1-t\rangle$ , again with $0\le t\le1$ . Then

$\displaystyle\int_{C_2}\langle x+9y,x^2\rangle\cdot\mathrm d\mathbf r_2=\int_{t=0}^{t=1}\langle9+t+9-9t,(9+t)^2\rangle\cdot\langle1,-1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(18-8t-(9+t)^2)\,\mathrm dt$
$=-\dfrac{229}3$

Finally,

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=108-\dfrac{229}3=\dfrac{95}3$

5 0

4 years ago

I need help with #14 & #15 quickly!

arsen [322]

Answer:

#14 $\frac{3m^{12} n^{10}-m^{8} n^{10}}4\\$ #15 $-448y^{32}x^{5}$