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Romashka-Z-Leto [24]
2 years ago
5

No Bots, Please answer asap. I need help.

Mathematics
1 answer:
skad [1K]2 years ago
3 0

Answer:

$3.864

Step-by-step explanation:

64% of 6.038 is 3.864

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Michelle needs to rent storage space for some of her belongings. She paid a one-
Lerok [7]

Answer:

c

Step-by-step explanation:

she pays a one-time fee of 50, and 15$ per month

7 0
2 years ago
Rotate rectangle ABCD 90ºccw about the origin. What<br> are the image coordinates?
bazaltina [42]

Answer:

Step-by-step explanation:

1. When rotating a point 90 degrees counterclockwise about the origin our point A(x,y) becomes A'(-y,x). In other words, switch x and y and make y negative.

2. The rule for a rotation by 180° about the origin is (x,y)→(−x,−y) .

3. Rotation of a point through 180°, about the origin when a point M (h, k) is rotated about the origin O through 180° in anticlockwise or clockwise direction, it takes the new position M' (-h, -k). ...

7 0
3 years ago
Brandon buys a radio for $48.17 in a state where the sales tax is 7%. How much does he pay in taxes? If necessary, round to the
shusha [124]

Answer:

49.0809

Step-by-step explanation:

Round it up to 49.10

8 0
2 years ago
How many dimensions does a point in space have
Andreas93 [3]

Hello, hope you are having a wonderful day.

A point has 0 dimensions. It has no length, width, or depth.

So any point in space has 0 dimensions.

Now, a line has 1 dimension.

Rectangles, squares and other shapes have 2 dimensions.

Cylinders, cubes, cones and other figures have 3 dimensions.

Hope it helps. Please mark Brainliest; I really need it.

~An emotional teen who helps others with joy

Good luck.

8 0
2 years ago
Please prove this........​
Crazy boy [7]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Given: A + B + C = π    →     C = π - (A + B)

                                    → sin C = sin(π - (A + B))       cos C = sin(π - (A + B))

                                    → sin C = sin (A + B)              cos C = - cos(A + B)

Use the following Sum to Product Identity:

sin A + sin B = 2 cos[(A + B)/2] · sin [(A - B)/2]

cos A + cos B = 2 cos[(A + B)/2] · cos [(A - B)/2]

Use the following Double Angle Identity:

sin 2A = 2 sin A · cos A

<u>Proof LHS → RHS</u>

LHS:                        (sin 2A + sin 2B) + sin 2C

\text{Sum to Product:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-\sin 2C

\text{Double Angle:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-2\sin C\cdot \cos C

\text{Simplify:}\qquad \qquad 2\sin (A + B)\cdot \cos (A - B)-2\sin C\cdot \cos C

\text{Given:}\qquad \qquad \quad 2\sin C\cdot \cos (A - B)+2\sin C\cdot \cos (A+B)

\text{Factor:}\qquad \qquad \qquad 2\sin C\cdot [\cos (A-B)+\cos (A+B)]

\text{Sum to Product:}\qquad 2\sin C\cdot 2\cos A\cdot \cos B

\text{Simplify:}\qquad \qquad 4\cos A\cdot \cos B \cdot \sin C

LHS = RHS: 4 cos A · cos B · sin C = 4 cos A · cos B · sin C    \checkmark

7 0
3 years ago
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