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Snezhnost [94]
2 years ago
12

Y= 4 5 x+1 y= – 3 5 x–6

Mathematics
1 answer:
aleksandrvk [35]2 years ago
8 0

Answer:

   

Step-by-step explanation:

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Determine whether the series is arithmetic or geometric. Then evaluate the finite series for the specified number of terms.
Paul [167]

Answer: it looks arithmetic if I had to guess

Step-by-step explanation:

5 0
3 years ago
In x² , what is the 2 called?
alexandr402 [8]

Answer:

<h2>an exponent</h2>

Step-by-step explanation:

In x², here the 2 is exponent while x is base.

7 0
3 years ago
Read 2 more answers
For every 20 litres of petrol a car can run for 75 km.
densk [106]

Answer:

<u>52.3 litres</u>.

Step-by-step explanation:

The car consumption is 75/20 = 3.75 km/litre.

Volume of petrol needed to travel 196 km

= 196 / 3.75 = 52.3 litres.

3 0
4 years ago
In a solar system, two comets pass near the sun, which is located at the origin. Comet E is modeled by quantity y plus 16 end qu
Leya [2.2K]

Explanation:

The equation of comet E is given below as

\frac{(y+16)^2}{400}+\frac{x^2}{144}=1

The equation of comet H is modelled below as

\frac{(y+13)^2}{144}-\frac{x^2}{25}=1

Given, that the Sun is located at the origin.

This is an equation of an ellipse. So, the path traveled by Comet e is an elliptic path.

Comparing with the Standard equation of ellipse: below,we will have

\frac{(y-k)^2}{b^2}+\frac{(x-h)^2}{a^2}

Whise center is

\begin{gathered} center=(h,k) \\ vertices=(h\pm a,0) \end{gathered}

By comparing coefficient, we will have

\begin{gathered} a^2=144 \\ a=12 \\ b^2=400 \\ b=20 \\ k=-16 \\ h=0 \\ (h,k)=(0,-16) \end{gathered}

Hence,

The vertex of comet E will be

\begin{gathered} (h\pm a,0) \\ (0+12,0),(0-12,0) \\ (12,0),(-12,0) \end{gathered}

The vertex of comet E is

(12,0),(-12,0)

Part C:

It is the foci forboth comets

\begin{gathered} cometE: \\ c=\sqrt{b^2-a^2} \\ c=\sqrt{400-144} \\ c=\sqrt{256} \\ c=16 \\  \\ For\text{ comet F:} \\ c=\sqrt{a^2-b^2} \\ c=\sqrt{144+25} \\ c=\sqrt{169} \\ c=13 \end{gathered}

Hence,

The foci will be

\begin{gathered} (16\pm16,0) \\ cometE \\ (0,0),(32,0) \\ cometF: \\ (13\pm13,0) \\ (0,0),(26,0) \end{gathered}

5 0
1 year ago
A student is trying to construct triangles using four different sets of angles. Th angles in each set are given below. Which set
sladkih [1.3K]

Well I can't be for sure but I know for a fact its not set IV it's not possible to make a triangle out of all right angles. Set II, well, that isn't right either. You can't make a triangle out of all obtuse angles. Like the right angle one, its not possible you can only use one obtuse or right angle in a triangle other wise it's not going to be a triangle. I'd say go try Set III since that would most likely make an equilateral triangle.

5 0
3 years ago
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