A 215 N box is placed on an inclined plane that makes a 35.0 degree angle with the horizontal. What applied force is needed to
1 answer:
The applied force that is needed to accelerate box up the incline is 208.66 N.
<h3 /><h3>The net force on the box</h3>The net force on the box is calculated by applying Newton's second law of motion.
where;
m is the mass of the box
The mass of the box is calculated as follows;
The applied force that is needed to accelerate box up the incline is calculated as follows;
Thus, the applied force that is needed to accelerate box up the incline is 208.66 N.
Learn more about net force here: brainly.com/question/14361879
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Answer:
(A) The wavelength of this wave is .
(B) The amplitude of this wave is .
Explanation:
Refer to the diagram attached. A point on this wave is at a crest or a trough if its distance from the equilibrium position is at a maximum.
The amplitude of a wave is the maximum displacement of each point from the equilibrium position. That's the same as the vertical distance between the crest (or the trough) and the equilibrium position.
- On the diagram, the distance between the two gray dashed lines is the vertical distance between a crest and a trough. According to the question, that distance is
for the wave in this rope.
- On the other hand, the distance between either gray dashed line and the black dashed line is the distance between a crest (or a trough) and the equilibrium position. That's the amplitude of this wave.
Therefore, the amplitude of the wave is exactly the vertical distance between a crest and a trough. Hence, for the wave in this question,
.
The wavelength of a transverse wave is the same as the minimum (horizontal) distance between two crests or two troughs. That's twice the horizontal distance between a crest and a trough in the same period.
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