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Olin [163]
2 years ago
12

A 215 N box is placed on an inclined plane that makes a 35.0 degree angle with the horizontal.  What applied force is needed to

accelerate box up the incline at 0.470 m/s2 if the force of friction is 75.0 Newtons?​
Physics
1 answer:
zloy xaker [14]2 years ago
7 0

The applied force that is needed to accelerate box up the incline is 208.66 N.

<h3 />

<h3>The net force on the box</h3>

The net force on the box is calculated by applying Newton's second law of motion.

\Sigma F = ma\\\\F - mgsin(\theta) - F_f = ma\\\\F = ma+ mgsin(\theta) + F_f

where;

m is the mass of the box

The mass of the box is calculated as follows;

W = mg\\\\m = \frac{W}{g} \\\\m = \frac{215}{9.8} \\\\m = 21.94 \ kg

The applied force that is needed to accelerate box up the incline is calculated as follows;

F = 21.94(0.47) \ + \ 215sin(35) \ + \ 75\\\\F = 208.6 6 \ N

Thus, the applied force that is needed to accelerate box up the incline is 208.66 N.

Learn more about net force here: brainly.com/question/14361879

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