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3 years ago

6

The brain is responsible for storing memories. How is this helpful for helping the body react to stimuli? ANSWER PLEASEEE

1 answer:

Murljashka [212]3 years ago

7 0

Answer:

Memories occur when specific groups of neurons are reactivated. In the brain, any stimulus results in a particular pattern of neuronal activity—certain neurons become active in more or less a particular sequence. ... Memories are stored by changing the connections between neurons. When the memories are stored, the stimuli can be recalled by being remembered. Explanation:

Hope it helps, I'm not 100% sure it's right though.

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Why must there be a chain at the bottom of a truck

MrRa [10]

Answer:

Known as automatic tire chains and sometimes referred to by brand names like Onspot or Insta-Chain, these chains essentially hang listlessly from the vehicle's suspension until inclement weather arrives. When that happens, a driver can flip a switch that will lower the chains so they hang in front of the back tires.

Explanation:

(Happy to Help)

7 0

3 years ago

What would be an example of a landform from magma

igomit [66]

I would say Lava.
Hope this helps. :)

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3 years ago

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What does an oceanic -oceanic convergence give rise to

FinnZ [79.3K]

i did the same test! Its volcanic island arcs

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3 years ago

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A 7.5 nC point charge and a - 2.9 nC point charge are 3.2 cm apart. What is the electric field strength at the midpoint between

Oduvanchick [21]

Answer:

Net electric field, $E_{net}=91406.24\ N/C$

Explanation:

Given that,

Charge 1, $q_1=7.5\ nC=7.5\times 10^{-9}\ C$

Charge 2, $q_2=-2.9\ nC=-2.9\times 10^{-9}\ C$

distance, d = 3.2 cm = 0.032 m

Electric field due to charge 1 is given by :

$E_1=\dfrac{kq_1}{r^2}$

$E_1=\dfrac{9\times 10^9\times 7.5\times 10^{-9}}{(0.032)^2}$

$E_1=65917.96\ N/C$

Electric field due to charge 2 is given by :

$E_2=\dfrac{kq_2}{r^2}$

$E_2=\dfrac{9\times 10^9\times 2.9\times 10^{-9}}{(0.032)^2}$

$E_2=25488.28\ N/C$

The point charges have opposite charge. So, the net electric field is given by the sum of electric field due to both charges as :

$E_{net}=E_1+E_2$

$E_{net}=65917.96+25488.28$

$E_{net}=91406.24\ N/C$

So, the electric field strength at the midpoint between the two charges is 91406.24 N/C. Hence, this is the required solution.

3 0

4 years ago

Determine the density of an object that has a mass of 149.8 g and displaces 12.1 mL of water when placed in a graduated cylinder

Crazy boy [7]

Answer:

"12.4 g/mL" would be the right solution.

Explanation:

The given values are:

Mass of the object,

= 149.8 g

Volume of the object,

= 12.1 mL

Now,

The Density will be:

⇒ $Density=\frac{Mass}{Volume}$

On substituting the given values in the above formula, we get

⇒ $=\frac{149.8}{12.1}$

⇒ $=12.4 \ g/mL$

6 0

3 years ago