1.
A graph is formed by plotting all pairs (x,y), such that y is f(x), for a certain function f.
for example:
Take a look at the graph. (x, y)=(3, 5) is on the graph. This means that f(3)=5 (because f(x)=y)
2.
The real solutions of a function f, are those points x, such that f(x)=0.
in the graph we see no point (x, 0), so there are no real solutions.
Answer: <span>No Real Solution</span>
Answer:
x value of vertical asymptote and y value of horizontal asymptote
Step-by-step explanation:
The graph of 1/x approaches infinity as x approaches 0 (the vertical asymptote)
As x gets either bigger or smaller, 1/x approaches the x-axis (from above on the positive side, from below on the negative side) (the horizontal asymptote)
Consider 1/(x-5) + 2, at what value of x does the graph 'go nuts' ?
When the bottom of the fraction becomes 0, x - 5 becomes 0 when x = 5, so the vertical asymptote of g(x) is at x=5
What value of y does f(x) approach as x gets more positive or more negative - as x gets bigger (as an example), y approaches 0
What y value does g(x) approach as x gets bigger? Well, as x gets big, 1/(x-5) gets small, approaching 0. The smallest 0 + 2 can get is 2, so y=2 is the horizontal asymptote
Answer:
D
Step-by-step explanation:
add everything up devide by 3
Answer:
x=60
Step-by-step explanation:
I'm assuming you meant this: (x/5)-8=4
In which case you would add 8 to both sides to get rid of the 8 on the left (your goal is to get x by itself so you want to move the numbers on the x side to the other side of the equal sign)
(x/5)=12
Then you would multiply 5 on both sides to get rid of the fraction with the 5 on the bottom on the left side.
x=60
There's your answer.
Answer:
3 twelths is your answer :)
