The answer would be one of the following in the photo below....if not do you have a picture you could show me of the possible answers?
Answer: 13300
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Work Shown:
A = event that it rains
B = event that it does not rain
P(A) = 0.30
P(B) = 1-P(A) = 1-0.30 = 0.70
Multiply the attendance figures with their corresponding probabilities
- if it rains, then 7000*P(A) = 7000*0.30 = 2100
- if it doesn't rain, then 16000*P(B) = 16000*0.70 = 11200
Add up the results: 2100+11200 = 13300
This is the expected value. This is basically the average based on the probabilities. The average is more tilted toward the higher end of the spectrum (closer to 16000 than it is to 7000) because there is a higher chance that it does not rain.
Answer:
A
Step-by-step explanation:
In the histogram described by the first option, the peak (18) is located at 40-50. Also, a frequency of zero is observed for range 10-20. The cluster from 20–50 means that most of the data is between this range, in fact, only 1 point is located at range 0 - 10, outside this cluster.
Answer:
D. 2058.24 in³
Step-by-step explanation:
Let r,h be the radius and height of smaller can and R,H be the radius and height of larger can
Then, R=4r and H=4h
Volume of smaller can=32.16 in³
⇒ πr²h=32.16 in³
Volume of larger can= πR²H
= π(4r²)×4h
= 64πr²h
= 64×32.16 in³
= 2058.24 in³
Hence, correct option is:
D. 2058.24 in³
The correct answer would be C
