How do the absolute values of -8 1/2 and -9 1/2 compare? Choose a symbol
1 answer:
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Answer:
x = - 1 ± i
Step-by-step explanation:
Given
3x² = - 12 - 6x ( add 6x to both sides )
3x² + 6x = - 12 ( divide through by 3 )
x² + 2x = - 4
To complete the square
add ( half the coefficient of the x- term )² to both sides
x² + 2(1)x + 1 = - 4 + 1
(x + 1)² = - 3 ( take the square root of both sides )
x + 1 = ± = ± i
( subtract 1 from both sides )
x = - 1 ± i
Answer:
x≤ −2/3y + −1/3
Step-by-step explanation:
because...
Step 1: Add -4y to both sides.
6x + 4y + −4y ≤ −2+−4y
6x ≤ −4y −2
Step 2: Divide both sides by 6.
6x/6 ≤
x ≤ −2/3y + −1/3
Therefor, the answer is x≤ −2/3y + −1/3
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