<span>Cancel <span>r2</span>
</span><span><span><span>(s4t)</span>/(</span><span>s<span>t3)</span></span></span>
2 <span>Use Quotient Rule: <span><span><span>xa/</span><span>xb</span></span>=<span>x^<span>a−b</span></span></span>
</span><span><span>s^<span>4−1</span></span><span>t^<span>1−3</span></span></span>
3 <span>Simplify <span>4−1</span> to 3
</span><span><span>s^3</span><span>t^<span>1−3</span></span></span>
4 <span>Simplify <span>1−3</span> to <span>−2</span>
</span><span><span>s^3</span><span>t^<span>−2</span></span></span>
5 <span>Use Negative Power Rule:<span><span>x^<span>−a</span></span>=<span>1/<span>xa</span></span></span>
</span><span><span>s^3</span>×<span>1/<span>t2</span></span></span>
6 <span>Simplify
</span><span><span>(s3)/(</span><span>t2)</span></span>
Done so the answer is a. then
Answer:
The correct answer is 10 and 14
Answer: l think it's none of the others
Step-by-step explanation:
Answer:
2 - 2<em>n</em>
Step-by-step explanation
We can use<em> n</em> for the number.
2 - 2(<em>n</em>)
2- 2<em>n</em>
Answer:
It will take 60 seconds for the signs to light up at the same time again.
Step-by-step explanation:
Given:
One sign lights up every 10 seconds
One sign lights up every 12 seconds
They have just lit up at the same time.
To find in how many seconds will it take for the signs to light up at the same time again.
Solution:
In order to find the time in seconds will it take for the signs to light up at the same time again, we need to find the least common multiple of the the times for which the given signs light up.
The numbers are 10 and 12.
To find the LCM, we will list the multiples of each and check the least common multiple.
The multiples of 10 and 12 are :
thus, we can see that 60 is the least common multiple.
Thus, the signs will light up at the same time time after every 60 seconds.
