The length of arc JL is So option c is correct.
<u>Solution:</u>
Given, from the diagram, radius of the given circle is 2 units.
And, the angle between the radius JK and KL is 125 degrees.
We have to find the length of the minor arc formed by JL
The length of arc is given as:
where is angle between radii formed by points with centre
Now the length of arc JL is:
Hence, the length of are JL is so option c is correct.
Answer:
710 ft
Step-by-step explanation:
8750 - 5200 = 3550
3550 / 5 = 710
Answer:
-1870n + 1044
Step-by-step explanation:
Answer:
See below
Step-by-step explanation:
<em>Vector argument</em>
Vector DF is (5, -4) - (5, 5) = (0, -9).
Vector EG is (2, 2) - (8, 2) = (-6, 0).
The dot-product of these two vector is (0, -9)•(-6, 0) = 0·(-6) + (-9)·0 = 0.
When the dot-product of two vectors is zero, those vectors are at right-angles to each other. Therefore diagaonal DF ⊥ diagonal EG.
_____
<em>Alternate argument</em>
The x-coordinates of points D and F are the same, so diagonal DF is a vertical line. The y-coordinates of points E and G are the same, so diagonal EG is a horizontal line. Vertical lines are perpendicular to horizontal lines, so DF ⊥ EG.
Answer:
45
Step-by-step explanation:
f(×) = 15x
f(3) = 15(3)
= 45
give brainliest please I need it to level up