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Dominik [7]
3 years ago
14

A salesperson is paid $140 per week plus 10% commission on her weekly sales of x dollars. Find a linear function that represents

her total weekly pay w in terms of x.
Mathematics
1 answer:
Verizon [17]3 years ago
4 0

Her weekly sales is X dollars

10% as a decimal is 0.10

Total commission is 0.10X ( 10% times weekly sales)

You then need to add that to her base pay of $140.

The equation is: w = 0.10x + 140

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80^2 - 45^2 = a^2 - b^2 <br><br> ans pls in working, thnx in advance
Kamila [148]

Answer:

{a}^{2}  -  {b}^{2}= {(80)}^{2}  -{(45)}^{2}  \\(a + b)(a - b) = (80 + 45)(80 - 45) \\  = 125 \times 35 = \boxed{ 4375}✓

<h3><u>4375</u> is the right answer.</h3>
4 0
2 years ago
Jessica spends $200 at a thrift shop.she spends $64 on rings and the rest on 4 equally priced bracelets which equation represent
Over [174]

Answer: The answer is B. Have a nice day.

Step-by-step explanation: Plz make brainliest. (I only need 1 more to become an expert!)

6 0
3 years ago
Rewa Delta Union Rugby CEO has become concerned about the slow pace of the rugby games played in the current union rugby, fearin
ozzi

Answer:

We conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

Step-by-step explanation:

We are given that Before the meeting, the mean duration of the 15-sided rugby game time was 3 hours, 5 minutes, that is, 185 minutes.

A random sample of 36 of the 15-sided rugby games after the meeting showed a mean of 179 minutes with a standard deviation of 12 minutes.

Let \mu = <em><u>mean duration of 15-sided union rugby games after the meeting.</u></em>

So, Null Hypothesis, H_0 : \mu \geq 185 minutes      {means that the mean duration of 15-sided union rugby games has increased or remained same after the meeting}

Alternate Hypothesis, H_A : \mu < 185 minutes     {means that the mean duration of 15-sided union rugby games has decreased after the meeting}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                            T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean duration of 15-sided union rugby games = 179 min

            s = sample standard deviation = 12 minutes

            n = sample of 15-sided rugby games = 36

So, <u><em>the test statistics</em></u>  =  \frac{179-185}{\frac{12}{\sqrt{36} } }  ~ t_3_5

                                       =  -3

The value of t test statistics is -3.

<u>Now, at 1% significance level the t table gives critical value of -2.437 at 35 degree of freedom for left-tailed test.</u>

Since our test statistic is less than the critical value of t as -3 < -2.437, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

6 0
3 years ago
To control pollination, pollen-producing flowers are often removed from the top of corn in a process called detasseling. The hou
Ivan

Answer:

z13 = 0.5, z17 = 2.5

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What is the relationship between the value of the digit 3 in 4,231 and in the value of the digit 3 in the number 3,421?
Marina CMI [18]

Answer:

A.

In 4231, the value of the digit 3 is 110 less than the value of the digit 3 in 3421.

Step-by-step explanation:

We can see that the value of 3 In 4231 is in ten while the value of 3 in 3421 is in thousands.

So to get the actual division factor, let's take 3300 and divide it by 30,

3300/30 = 110

So it's clear already, that the value of 3 in 4231 is 110 times less to the value in 3421

4 0
3 years ago
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