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vitfil [10]
3 years ago
14

Anyone help???????????

Mathematics
2 answers:
Marta_Voda [28]3 years ago
8 0

Answer:

Graph A

hope it helps

Step-by-step explanation:

Lisa [10]3 years ago
4 0
Graph A is the answer hope it helped you :)
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Points b d and f are midpoints of ten sides of ace ec=44 df=25 find ac
scZoUnD [109]

Answer:

The length of AC is;

C. 50

Step-by-step explanation:

By the midpoint of a triangle theorem, we have that a segment that spans across and intersects with the midpoints of two sides of a triangle is equal to half the length of the third side and parallel to the length of the third side

The given parameters are;

The midpoints of ΔACE are B, D, and F

The length of EC = 44

The length of DF = 25

Therefore, we have;

Given that DF is a midsegment of triangle ΔACE, then DF ║ AC and

the length of DF = (1/2) × AC the length of AC

∴ The length of AC = 2 × The length of DF

The length of DF = 25

∴ The length of AC = 2 × 25 = 50

The length of AC = 50

4 0
2 years ago
In the figure, line L1 is parallel to line L2. If the measure of ∠4 = 144°, what is the measure of ∠6 and why? A. 144°, vertical
Brrunno [24]

Answer:the answer is B

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Find the center and radius of x^2+y^2+2x-10y+10=0
kumpel [21]
r^{2} = 16
r=4
(xh)^{2}2+(y-k)2=(x+1)2 +(y-5)2
h=-1,k=5
3 0
3 years ago
What is the y-intercept of this equation?<br> y= 2/9x +13
Ksju [112]

Answer:

13

Step-by-step explanation:

y=mx+b

b= y-intercept

5 0
3 years ago
Read 2 more answers
Three Nissans, two Fords, and four Chevrolets can be rented for $106 per day. At the same rates two Nissans, four Fords, and thr
Sindrei [870]

Answer:

The rental rate for the Fords is of $12 per day.

Step-by-step explanation:

This question is solved using a system of equations.

I am going to say that:

x is the cost of a Nissan.

y is the cost of a Ford.

z is the cost of a Chevrolet.

Three Nissans, two Fords, and four Chevrolets can be rented for $106 per day.

This means that:

3x + 2y + 4z = 106

Two Nissans, four Fords, and three Chevrolets cost $107 per day

This means that:

2x + 4y + 3z = 107

Four Nissans, three Fords, and two Chevrolets cost $102 per day.

This means that:

4x + 3y + 2z = 102

From the first equation:

4z = 106 - 3x - 2y

2z = 53 - 1.5x - y

z = 26.5 - 0.75x - 0.5y

Replacing into the third equation:

4x + 3y + 53 - 1.5x - y = 102

2.5x + 2y = 49

From the second equation:

2x + 4y + 3z = 107

2x = 107 - 4y - 3z

x = 53.5 - 2y - 1.5z

x = 53.5 - 2y - 1.5(26.5 - 0.75x - 0.5y)

x - 1.125x = 53.5 - 2y - 39.75 + 0.75y

-0.125x = 13.75 - 1.25y

0.125x = 1.25y - 13.75

x = \frac{1.25y - 13.75}{0.125}

x = 10y - 110

Find the rental rate for the Fords.

We have to find y, so:

2.5x + 2y = 49

2.5(10y - 110) + 2y = 49

25y - 275 + 2y = 49

27y = 324

y = \frac{324}{27}

y = 12

The rental rate for the Fords is of $12 per day.

3 0
3 years ago
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