Answer:
x = -2
TU = 4
UB = 2
Step-by-step explanation:
you can add x^2 with 4x+10 and equate it to 6:
x^2 + 4x + 10 = 6
x^2 + 4x + 4
then u can use the roots formula : x = (-b ± √ (b2 - 4ac) )/2a
so it'll be x = {-4±[√16 - 4(4)]}/2
x= -2
then u can substitute it and find TU and UB
TU= (-2)^2 = 4
UB= 4(-2)+10 = 2
An outlier is a point which falls more that 1.5 times the interquartile range above the thrid quartile or below the first quartile. It is basically the point which is abnormally off the limit within which other points are within. Given our data points:
1300, 18,25,18,-7,24
compared to the rest of the points, 1300 is quite of the limit. Thus;
Answer: 1300
Answer:
y - 4 = (1/3)(x - 9) or x - 3y = -3
Step-by-step explanation:
Here we're told that the slope is 1/3 and that (9, 4) is a point on the line. Use the point-slope formula y - k = m(x - h). Substitute 4 for k, 9 for h and 1/3 for m:
y - 4 = (1/3)(x - 9) (point-slope formula)
3y - 12 = x - 9 (standard form of the same equation) = >
-12 + 9 = x - 3y, or x - 3y = -3 (standard form)
Answer:
a0 = 4
Step-by-step explanation:
- 6xy^-2/x^-3 =
- 6xx^3/y^2 =
- 6x^4/y^2
- a0 = 4
Answer:
Step-by-step explanation:I don't say you have to mark my ans as brainliest but if you think it has really helped you please don't forget to thank me ...
