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3 years ago

PLEASE HELP IM BEING TIMED!

Mathematics

2 answers:

seraphim [82]3 years ago

3 0

The answer is He needs 1/3 more cups of flour than he has.

(2 2/3) x 2 = 16/3 = 5 1/3

eimsori [14]3 years ago

3 0

The recipe calls for 2 cups of flour. The double of this amount is :

$\mathfrak{2*2}$

$\underline{\mathfrak{=4}}$

If Ivan has 5 cups, then :

$\mathfrak{5-4}$

$\underline{\mathfrak{=1}}$

So, O A. Ivan has 1 cup of flour more than he needs.

$\mathbb{MIREU}$

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Factorise the following.

Alika [10]

Answer:

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49x²-16/25= (7x)²- (4/5)²=(7x+4/5)(7x-4/5)

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3 years ago

Read 2 more answers

Which expression is equivalent to 3 square root of 125

Nookie1986 [14]

Answer:

The √125 can be factored out to 25 and 5 then 25 can be factored out to 5 and 5. Then you pair up the numbers, you have a pair of 5's and a 5 left over. So the pair of 5's goes inside the radical as √5 and on the outside of the radical you have 5×3. So 3√125≈15√5.

Step-by-step explanation:

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4 years ago

Let p = the product of all the odd integers between 500 and 598, and let q = the product of all the odd integers between 500 and

ANEK [815]

Answer:

$\frac{360000q}{359999}$

Step-by-step explanation:

p = Product of all odd integers between 500 an 598. So,

p = 501 x 503 x 505 ... x 595 x 597

q = Product of all odd integers between 500 and 602. So,

q = 501 x 503 x 505 ... x 595 x 597 x 599 x 601

From the above relations, we can see that q is equal to p multiplied by 599 and 601. i.e.

q = p x 599 x 601

or,

$p=\frac{q}{599 \times 601}$

We need to evaluate 1p + 1q in terms of q. Using the value of p from above expression, we get:

$p+q=\frac{q}{599 \times 601} + q\\\\ p+q=\frac{q+(599 \times 601q)}{599 \times 601}\\ \\ p+q=\frac{q(1+599\times601)}{599 \times 601}\\\\ p+q=\frac{360000q}{359999}$