A slice that cuts across a corner through three sides of a cube

I need to find the table of -csc theta

AVprozaik [17]

See below for the table of -csc theta

<h3>How to determine the table?</h3>

The function is given as:

-csc theta

Rewrite properly as:

$-\csc(\theta)$

This is calculated as:

$-\csc(\theta) = -\frac{1}{\sin(\theta)}$

Set $\theta$ to 0, 30, 45, 60 and 90

$-\csc(0) = unde fined$

$-\csc(30) = -2$

$-\csc(45) = -\sqrt 2$

$-\csc(60) = -\frac{2\sqrt 3}{3}$

$-\csc(90) = -1$

So, the table of -csc theta is

Angle -csc theta

0 undefined

30 -2

45 -√2

60 -2/3 √3

90 -1

Read more about trigonometry functions at:

brainly.com/question/17332981

#SPJ1

8 0

2 years ago

PLEASE HELP !!!!!

stepan [7]

Answer:

1) y = 1.8741176487x + 3.655964863

2) About $191 using the equation, about $180 or more using the data you are given.

3) I can use the regression calculator by using the largest number of customers you have in the data set and lowest number of customers and compare them to see if the numbers are in ascending or descending order.

7 0

3 years ago

Scot wants to buy a scooter that cost $129 this is$24 more than 3 times what He saved last month how much he did save last month

Lostsunrise [7]

Total $129

129 - 24 = 105

105 / 3 = 35

Scot saves $35 last month

5 0

3 years ago

Read 2 more answers

(3,-3) polar coordinates

tamaranim1 [39]

Answer:

-1

Step-by-step explanation:

7 0

4 years ago

Read 2 more answers

Suppose a random sample of 100 observations from a binomial population gives a value of pˆ = .63 and you wish to test the null h

irakobra [83]

Answer:

We conclude that the population proportion is equal to 0.70.

Step-by-step explanation:

We are given that a random sample of 100 observations from a binomial population gives a value of pˆ = 0.63 and you wish to test the null hypothesis that the population parameter p is equal to 0.70 against the alternative hypothesis that p is less than 0.70.

Let p = population proportion.

(1) The intuition tells us that the population parameter p may be less than 0.70 as the sample proportion comes out to be less than 0.70 and also the sample is large enough.

(2) So, Null Hypothesis, $H_0$ : p = 0.70 {means that the population proportion is equal to 0.70}

Alternate Hypothesis, $H_A$ : p < 0.70 {means that the population proportion is less than 0.70}

The test statistics that would be used here One-sample z-test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion = 0.63

n = sample of observations = 100

So, the test statistics = $\frac{0.63-0.70}{\sqrt{\frac{0.70(1-0.70)}{100} } }$

= -1.528

The value of z-test statistics is -1.528.

Now at 0.05 level of significance, the z table gives a critical value of -1.645 for the left-tailed test.

Since our test statistics is more than the critical value of z as -1.528 > -1.645, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the population proportion is equal to 0.70.

(c) The observed level of significance in part B is 0.05 on the basis of which we find our critical value of z.

4 0

3 years ago