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Roman55 [17]
2 years ago
9

Please help me quickly

Mathematics
1 answer:
bekas [8.4K]2 years ago
4 0

Answer:

D

when you look at it it is upside down so d is the right answer

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3 years ago
Pls help me solve this
prisoha [69]
B, because it’s saying 119 and over you can play on the junior varsity football team.
8 0
3 years ago
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George bought 7.5 cases of pancake mix for his diner. A case contains 12 1.3-pound boxes. How many pounds of pancake mix did Geo
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2 years ago
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Find the exact value of tan (arcsin (two fifths)). For full credit, explain your reasoning.
Hitman42 [59]
\bf sin^{-1}(some\ value)=\theta \impliedby \textit{this simply means}
\\\\\\
sin(\theta )=some\ value\qquad \textit{now, also bear in mind that}
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sin(\theta)=\cfrac{opposite}{hypotenuse}\qquad 
\qquad 
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}\\\\
-------------------------------\\\\

\bf sin^{-1}\left( \frac{2}{5} \right)=\theta \impliedby \textit{this simply means that}
\\\\\\
sin(\theta )=\cfrac{2}{5}\cfrac{\leftarrow opposite}{\leftarrow hypotenuse}\qquad \textit{now let's find the adjacent side}
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\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}

\bf \pm \sqrt{5^2-2^2}=a\implies \pm\sqrt{21}=a
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\textit{we don't know if it's +/-, so we'll assume is the + one}\quad \sqrt{21}=a\\\\
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tan(\theta)=\cfrac{opposite}{adjacent}\qquad \qquad tan(\theta)=\cfrac{2}{\sqrt{21}}
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\textit{and now, let's rationalize the denominator}
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\cfrac{2}{\sqrt{21}}\cdot \cfrac{\sqrt{21}}{\sqrt{21}}\implies \cfrac{2\sqrt{21}}{(\sqrt{21})^2}\implies \cfrac{2\sqrt{21}}{21}

7 0
3 years ago
How to solve the problem
WINSTONCH [101]
As tgose lines are parallel then,

a = 140° ( by alternate interior angles)

then,
tha angle just below "a" on the other paralle line would also be 140° by corresponding angles,

using exterior angle property of triangle

66° + b = 140°

b = 140° -66
= 74°
7 0
3 years ago
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