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swat32
2 years ago
6

The G&T Guild Charter uses some terminologies that contain the word Treasure'. Identify these terminologies.

Computers and Technology
1 answer:
zvonat [6]2 years ago
5 0

Answer:

treasure, that is what you are.

baby you're my favorite star.

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Write a program that prompts the user to enter a string (may contain spaces) and displays its last character. Enter s string: Pr
STALIN [3.7K]

Answer:

<em>The programming language in Python is as follows:-</em>

#Prompt user for input string

userinput = input("Enter a string: ")

#Print the last character of the input

print("The last character is "+userinput[-1])

#End of Program

Explanation:

This line is a comment

#Prompt user for input string

This line prompts user for input

userinput = input("Enter a string: ")

This line is also a comment

#Print the last character of the input

This next line prints the last character of the input string; the last character is defined by the index -1

print("The last character is "+userinput[-1])

3 0
3 years ago
Do earthquakes ever happen in Malaysia?​
adoni [48]

The correct answer to this open question is the following.

Although there are no options attached we can say the following.

Do earthquakes ever happen in Malaysia?

Yes, they do. And they are very frequent and high in intensity.

For instance, the Sabah earthquake in 2015.

On June 5, 2015, the region of Malaysia was hit by a strong earthquake, 6.0 of magnitude on the Ritcher scale. The telluric movement lasted 30 seconds and caused much destruction.

Experts and scientists confirm that this had been the strongest earthquake since the one presented in 1976.

8 0
3 years ago
Synthesizing information can be done by creating
Maurinko [17]

Answer:

D

Explanation:

because you use all of those

4 0
4 years ago
Read 2 more answers
How are network computers different from traditional personal computers? describe some usage scenarios in which it is advantageo
Elanso [62]
A network computer depend on on a centralized computer for most of its services. It can consequently have a minimal operating system while a personal computer on the other hand has to be proficient of on condition that all of the required functionality in a detached manner without depending on a centralized manner. Scenarios where administrative costs are high and where sharing leads to more efficient use of resources are exactly those settings where network computers are preferred.
8 0
4 years ago
A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st
Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

^nC_r = \frac{n!}{(n-r)!r!}

Where n = 15\ and\ r = 4

^{15}C_4 = \frac{15!}{(15-4)!4!}

^{15}C_4 = \frac{15!}{11!4!}

^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}

^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}

^{15}C_4 = \frac{32760}{24}

^{15}C_4 = 1365

<em>Hence, there are 1365 ways </em>

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

<em>From the given parameters; 3 out of 15 is detective;</em>

So;

p = 3/15

p = 0.2

q = 1 - p

q = 1 - 0.2

q = 0.8

Solving further using binomial;

(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

Probability =  ^nC_3pq^3

Substitute 4 for n, 0.2 for p and 0.8 for q

Probability =  ^4C_3 * 0.2 * 0.8^3

Probability =  \frac{4!}{3!1!} * 0.2 * 0.8^3

Probability = 4 * 0.2 * 0.8^3

Probability = 0.4096

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

<em>Probability that at least one is defective + Probability that at none is defective = 1</em>

Probability that none is defective is calculated as thus;

Probability =  q^n

Substitute 4 for n and 0.8 for q

Probability =  0.8^4

Probability = 0.4096

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

8 0
3 years ago
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