Answer:
120 seconds
Step-by-step explanation:
To solve this question you have to make equation of both gallon.
Gallon 1 have 130 gallons of water at the start and filled by 1/4 gallon each second. If x equal to the time in seconds, the equation of gallon 1 volume will be:
g1= 130+ 1/4x
Gallon 1 have 200 gallons of water at the start and drained by 1/ 3 gallon each second, the equation of gallon 2 volume :
g2= 200- 1/3x
When gallon 1 volume equal to gallon 2, it mean g1=g2
g1= g2
130+ 1/4x = 200- 1/3x
130- 200= -1/3x -1/4x
-70= - 4/12x - 3/12x
-7/12x= -70
7/12x= 70
x= 70*12/7
x= 120
Answer:
Step-by-step explanation:
Exponent law:


First convert radical form to exponent form and then apply exponent law.



Answer: The Mean is 12 while the median is 10.
Step-by-step explanation: To find the mean we need to add all points scored which equals 108 points. Next, you will divide this by the number of players that scored points. Because there are 9 players we will follow 108/9=12. To find the median, you write out each number from smallest to largest or largest to smallest and find the number in the middle, this should act somewhat like an average however i would recommend using the mean to find an average. When writing out all the number they should look something like this: 6,7,7,7,10,11,13,23,24
Now that we have written them out, we find the middle most number which is 10 which means that our median is 10.
The mean is 12 points.
The median is 10 points.
<em>Answer: There are 5 trumpet players and 15 saxophone player</em>
<em>Step-by-step explanation: Let a be the number of trumpet players
</em>
<em>Let b be the number of saxophone players
</em>
<em>---------------------
</em>
<em>(1) a = b-10
</em>
<em>(2) b =3a
</em>
<em>----------------
</em>
<em>Substitute </em>
<em>(2) into (1)
</em>
<em>(1) a =3a-10
</em>
<em>(1) 2a =10 </em>
<em>
</em>
<em> (1) a = 5and
</em>
<em>(2) b = 3(5)(2) </em>
<em>b = 15
</em>
<em>------------------
</em>
<em>There are 5 trumpet players and 15 saxophone player</em>
Average rate of change over the interval <span><span>[a,b]</span>
</span> for <span><span>y=<span>f<span>(x)</span></span></span>
</span> is given by <span><span><span><span>f<span>(b)</span></span>−<span>f<span>(a)</span></span></span><span>b−a</span></span>
</span>
Hence, average rate of change of from <span><span>x=−2</span>
</span> to <span><span>x=6</span>
</span> i.e. over the interval <span><span>[−2,6]</span>
</span> for <span><span>y=<span>f<span>(x)</span></span>=<span>12</span><span>x2</span></span>
</span> is given<span><span> rate of change=<span><span><span>f<span>(6)</span></span>−<span>f<span>(−2)</span></span></span><span>6−<span>(−2)</span></span></span></span>
</span>
As <span><span><span>f<span>(−2)</span></span>=<span>12</span><span><span>(−2)</span>2</span>=2</span>
</span> and <span><span><span>f<span>(6)</span></span>=<span>12</span><span><span>(6)</span>2</span>=</span>
</span><span>rate of change=<span><span>18−2</span>8</span>=<span>162</span>=<span>2</span></span>