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3 years ago

How many real roots does the function f(x)=x^2+8x-2

2 answers:

6 0

Using the discriminant
for
f(x)=ax²+bx+c

the discriminant is b²-4ac
when it is
1. less than 0, there are no real roots
2. equal to 0, then there is 1 real root
3. more than 0, 2 real roots

given
f(x)=1x²+8x-2
a=1
b=8
c=-2
discriminat
8²-4(1)(-2)
64+8
this is greater than 0
2 real roots

galina1969 [7]3 years ago

3 0

First find the determinant, Δ = b^2 - 4ac
a = 1, b = 8 , c = -2 
Δ = 8^2 - 4*1*-2 
Δ = 64 + 8 
Δ = 72 > 0 
therefore there are two real roots!

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2 years ago

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3 years ago

Select yes or no to indicate whether a zero must be written in the dividend to find the quotient

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2.25 divided by 0.6 : Yes and 5.2 divided by 8, 3.63 divided by 3, 71.1 divided by 9 : No

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We have that when two numbers are divided, they can be written in the form $\frac{p}{q}$ , where p is the dividend and q is the divisor.

Now, when we divide 5.2 by 8, we can write $\frac{5.2}{8}$

Also, the division 3.63 by 3, can be written as $\frac{3.63}{3}$ = 1.21

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3 years ago