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enyata [817]
2 years ago
9

A train is moving at a rate of 65 miles/hour toward a railroad marker located 200 miles away. Which equation could be used to fi

nd the time it will take for the distance between the train and the railroad marker to be 4 miles, where h represents the time in hours?
Mathematics
1 answer:
yulyashka [42]2 years ago
5 0

Answer:

h = 196/65

Step-by-step explanation:

65 miles /1 hour is the moving rate

200 miles is the distance to the railroad maker

h = ?

200- 4 miles = 196 miles were left behind the train

65miles /1 hour , 130miles/2hours , ..196miles/ ?hours

h = 196/65 = 3 hours and 1/65 minutes from an hour = 3 hours and 12/13 min.

60/ 65 = 12/13

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H(y)=9/5 • 2y at y=-2
Deffense [45]

Answer:

H( - 2) = - 7  \frac{1}{5}

Step-by-step explanation:

We want to evaluate the equation

H(y) =  \frac{9}{5}  \times 2y

at y=-2

We just have to substitute to obtain;

H( - 2) =  \frac{9}{5}  \times 2 \times  - 2

We now multiply to get:

H( - 2) =  \frac{9}{5}   \times  - 4

This is the same as:

H( - 2) =  \frac{9}{5}  \times \frac{ - 4}{1}

We multiply the numerators separately and denominators separately to get:

H( - 2) =  \frac{9 \times  - 4}{5 \times 1}

H( - 2) =  \frac{ - 36}{5}

This implies that

H( - 2) = - 7  \frac{1}{5}

6 0
3 years ago
What type of association does the following scatter plot represent?
yarga [219]

Answer:

Negative linear association.

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
When making a long distance call from a certain pay phone, the first three minutes of a call cost $2.10. After that, each additi
Sauron [17]

Answer: the number of minutes of long distance call that one can make is lesser than or equal to 12 minutes.

Step-by-step explanation:

Let x represent the number of minutes of long distance call that one makes.

The first three minutes of a call cost $2.10. After that, each additional minute or portion of a minute of that call cost $0.45. This means that if x minutes of long distance call is made, the total cost would be

2.10 + 0.45(x - 3)

Therefore, the inequality to find the number of minutes one can call long distance for $6.15 is expressed as

2.10 + 0.45(x - 3) ≤ 6.15

2.10 + 0.45x - 1.35 ≤ 6.15

0.75 + 0.45x ≤ 6.15

0.45x ≤ 6.15 - 0.75

0.45x ≤ 5.4

x ≤ 5.4/0.45

x ≤ 12

4 0
3 years ago
Just do b d f h and j​
Andrew [12]

Answer:

b) 1.383

d) 2733

f) 41.429

h) 6317

j) 87.889

Step-by-step explanation:

4 0
2 years ago
Carlos can ride his bike 30 km in 2 hours. At the same rate, how far can he ride in 7 hours?
lozanna [386]
He can ride his bike 105 km. 30/2 is 15. 15*7 is 105.

:D

5 0
3 years ago
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